Answer:
I will assume that “maximum force” implies the constant application of power P = 400 hp (international) to accelerating the vehicle. The force will therefore vary with speed as the vehicle accelerates. I will also assume that all engine energy goes into accelerating the vehicle, rather than rotating elements like its wheels.
In this case the 400 hp (equivalent to 298,280 watts) is applied for time t = 2 seconds. Therefore the kinetic energy of the vehicle is increased by:
ΔKE=Pt=(298,280)(2)=596,560 joules.
The initial kinetic energy is:
KEinitial=12mv2
=(0.5)(1600)(82)=51,200 joules.
Therefore final kinetic energy is:
KEfinal=KEinitial+ΔKE
=51,200+596,560
=647,760 joules
Therefore final vehicle velocity can be found:
KEfinal=12mv2
v=2KEfinalm−−−−−−−−√
=(2)(647,760)1600−−−−−−−−−−−√
= 28.455 m/s
Explanation:
Answer:
90 meters.
Explanation:
The correct answer is: B.) 90 m
Answer
given,
largest diameter of balls = 9.52 mm = 0.00476 m
radius = 0.00476
smallest diameter of ball = 2.38 mm = 0.00238 m
radius = 0.00119
viscosity = 1.5 Pa.s
density of the ball = 1.42 g/cm
for small balls
t = 0.033 ms
for larger ball
t = 0.531 ms
Answer: static stretching
Explanation:
e.g rubberband
To determine the velocity of the roller coaster as it moves down, we use the kinematic equation which is expressed as 2gy = vf^2 - v0^2 where g is the gravitational acceleration, y is the elevation of the roller coaster, vf and vo are the final and initial velocity. We calculate as follows:
2gy = vf^2 - v0^2
Since it starts at rest, v0 is zero.
2gy = vf^2
vf = √2gy
vf = √2(9.8)(101)
vf = 44.5 m/s
