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Eddi Din [679]
3 years ago
7

An orange might roll off your cafeteria tray when you stop suddenly because of

Physics
1 answer:
Rina8888 [55]3 years ago
8 0
Inertia: <span>The </span>law<span> of </span>inertia says <span>that an object at rest stays at rest and an object in motion stays in motion unless a force does something.</span>
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a 1 gram spiders sits on a platform rotating at 78 rpm. the spider is 15 cm from the centre disk. find the speed of the spider
olga nikolaevna [1]

The spider is traveling in a circle with radius = 15cm

The circumference of any circle = <em>2 pi (radius)</em>
The circumference of the spider's path = 2 pi (15 cm) = 30 pi cm

The spider completes a trip around this path 78 times per minute.
Its speed, relative to you, is   

                               (78) x (30 pi) cm/min =

                                       2,340 pi cm/min =  7,351.33 cm/min =

                                     <em>  73.5133 meter/min =</em>

                                       <em>4.411 km/hr =</em>

                                         <em>2.74  miles/hour

</em>
(After the last appearance of pi,
all numbers are rounded.)<em>

</em>
8 0
4 years ago
Which of the following is contained in a pull start lawnmower?
Ksivusya [100]
A wheel and axle and an inclined plane.
6 0
3 years ago
Read 2 more answers
When a burning stick of increase is moved fast in a circle a circle of red light is seen.​
anzhelika [568]

Answer:

The impression of the image on the retina lasts for about 1/16th of a second after the removal of the object. If a burning stick of incense is revolved at a rate of more than sixteen revolutions per second, we see a circle of red light due to persistence of vision.

Explanation:

7 0
3 years ago
PLEASE HELP MEEEE<br> ITS SIMPLE BUT CONFUSING
avanturin [10]

The density of Liquid T is less than that of water.

So, Liquid T will float on water.

<h3>Answer:</h3>

D. Liquid T

7 0
3 years ago
Read 2 more answers
A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.2 m/s. The car is a distanc
dem82 [27]

Explanation:

It is known that the relation between speed and distance is as follows.

               velocity = \frac{distance}{time}

As it is given that velocity is 6 m/s and distance traveled by the bear is (d + 29). Therefore, time taken by the bear is calculated as follows.

         t_{bear} = \frac{(d + 29)}{6 m/s} ............. (1)

As the tourist is running in a car at a velocity of 4.2 m/s. Hence, time taken by the tourist is as follows.

              t_{tourist} = \frac{d}{4.2} ............. (2)

Now, equation both equations (1) and (2) equal to each other we will calculate the value of d as follows.

              t_{bear} = t_{tourist}

       \frac{(d + 29)}{6 m/s} = \frac{d}{4.2}

                   4.2d + 121.8 = 6d

                         d = \frac{121.8}{1.8}

                            = 67.66

Thus, we can conclude that the maximum possible value for d is 67.66.

5 0
3 years ago
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