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Yuri [45]
3 years ago
6

A dart is loaded into a spring-loaded toy dart gun by pushing the spring in by a distance d. For the next loading, the spring is

compressed a distance 8d. How much work is required to load the second dart compared to that required to load the first?
Physics
1 answer:
Aliun [14]3 years ago
8 0

Answer:

the work required for the loading of second dart is 64 times greater as work required for loading the first dart.

Explanation:

k = spring constant of the spring loaded toy dart gun

x₁ = compression of spring to load the first dart = d

x₂ = compression of spring to load the second dart = 8 d

E₁ = Work required to load the first dart

E₂ = Work required to load the second dart

Work required to load the first dart is given as

E₁ = (0.5) k x₁² = (0.5) k d²

Work required to load the second dart is given as

E₂ = (0.5) k x₂² = (0.5) k (8d)² = (64) (0.5) k d²

E₂ = 64 E₁

So the work required for the loading of second dart is 64 times greater as work required for loading the first dart

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now by above formula

M = \frac{4 \pi^2 r^3}{GT^2}

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Part c)

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now by above formula

M = \frac{4 \pi^2 r^3}{GT^2}

M = \frac{4 \pi^2 (10.7 * 10^8)^3}{(6.67 * 10^{-11})(618624)^2}

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6 0
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Why are different constellations<br> of stars seen during different<br> seasons?
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The Earth spins once a day. You spin along with the Earth, and your clock is
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