To solve the problem, it is necessary the concepts related to the definition of area in a sphere, and the proportionality of the counts per second between the two distances.
The area with a certain radius and the number of counts per second is proportional to another with a greater or lesser radius, in other words,
M,m = Counts per second
Our radios are given by
Therefore replacing we have that,
Therefore the number of counts expect at a distance of 20 cm is 19.66cps
In general, that's not possible, unless the three numbers relate to
very specific quantities.
For example, if the three numbers are the object's height, temperature,
and cost, then they are of no help at finding the object's velocity.
Answer:
The size of the force that pushes the wall is 12,250 N.
Explanation:
Given;
mass of the wrecking ball, m = 1500 kg
speed of the wrecking ball, v = 3.5 m/s
distance the ball moved the wall, d = 75 cm = 0.75 m
Apply the principle of work-energy theorem;
Kinetic energy of the wrecking ball = work done by the ball on the wall
¹/₂mv² = F x d
where;
F is the size of the force that pushes the wall
¹/₂mv² = F x d
¹/₂ x 1500 x 3.5² = F x 0.75
9187.5 = 0.75F
F = 9187.5 / 0.75
F = 12,250 N
Therefore, the size of the force that pushes the wall is 12,250 N.
Answer:
Please find the answer in the explanation
Explanation:
Given that Force affects the body and results in different changes.
The grid that has the words related to the effects of force are :
a) Force could be a push or a pull.
c) Force has magnitude as well as direction.
e) Force acting on an object may cause a change in its state of motion or a change in its shape.
f) A force can act on an object with or without being in contact with it.
Answer:
my butt
Explanation:
2x2 by the power of 10 divide that 98
