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Yuri [45]
4 years ago
6

A dart is loaded into a spring-loaded toy dart gun by pushing the spring in by a distance d. For the next loading, the spring is

compressed a distance 8d. How much work is required to load the second dart compared to that required to load the first?
Physics
1 answer:
Aliun [14]4 years ago
8 0

Answer:

the work required for the loading of second dart is 64 times greater as work required for loading the first dart.

Explanation:

k = spring constant of the spring loaded toy dart gun

x₁ = compression of spring to load the first dart = d

x₂ = compression of spring to load the second dart = 8 d

E₁ = Work required to load the first dart

E₂ = Work required to load the second dart

Work required to load the first dart is given as

E₁ = (0.5) k x₁² = (0.5) k d²

Work required to load the second dart is given as

E₂ = (0.5) k x₂² = (0.5) k (8d)² = (64) (0.5) k d²

E₂ = 64 E₁

So the work required for the loading of second dart is 64 times greater as work required for loading the first dart

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Two point charges exert a 6.10 N force on each other. What will the force become if the distance between them is increased by a
anzhelika [568]

Answer:

0.0953125 N

Explanation:

Applying,

F = kq'q/r²................. Equation 1

Where F = electrostatic force, k = coulomb's constant, q' and q = first and second charge respectively, r = distance between the charge.

From the equation,

If both charges remain constant,

Therefore,

F = C/r²

C = Constant =  product of the two charge(q' and q) and k

Fr² = F'r'²................ Equation 2

From the question,

Given: F = 6.10 N

Assume: r = x m, r' = 8x

Substitute these value into equation 2

6.1(x²) = F'(8x)²

F' = 6.1/64

F' = 0.0953125 N

Hence the new force will become 0.0953125 N

5 0
3 years ago
An object moves from position +34m to the position -15m in 15 seconds. What is the total displacement? What is the total velocit
Alexandra [31]

1) Displacement: -49 m, in the negative direction

Explanation:

The displacement of an object is a vector, whose magnitude is given by the difference between the final point of the motion and the starting point:

d=p_f -p_i

In this problem, the starting point is +34 m, while the final position is -15 m; therefore, the displacement is:

d=-15 m- (+34 m)=-49 m

and the direction is negative, in according to the negative sign.


2) Velocity: -3.27 m/s

Explanation:

Velocity is equal to the ratio between the displacement and the time taken:

v=\frac{d}{t}

in this problem, we have:

d = -49 m is the displacement

t = 15 s is the time

therefore, the velocity is

v=\frac{-49 m}{15 s}=-3.27 m/s

and the direction is negative.

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I believe the answer is true
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