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Makovka662 [10]
3 years ago
6

Write 3.088 as a mixed number and improper fraction

Mathematics
1 answer:
mixas84 [53]3 years ago
8 0

Answer:

Mixed number-3 and 88/1000 which is simplified to 3 and 11/125

Improper fraction- 386/125

Step-by-step explanation:

<u>Mixed Number</u>

3.088 is read as Three and eighty-eight thousandths. As a fraction we write this as 3 and 88/1000. However, 88/1000 can be simplified. The greatest common factor that will go into 88 and 1000 is 8, so I divide 8 into 88 and get 11, then I divide 8 into 1000 and get 125. Simplified my answer is 3 and 11/125.

<u>Improper Fraction</u>

If I have 3 and 11/125, I will change it to an improper fraction by first multiplying the whole number 3 by the denominator 125. This gives me 375, which I add to the numerator 11 and that gives me 386. I will keep my denominator so my improper fraction will be 386/125.








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2564.0 millimeters tall. If the boards are too long they must be trimmed, and if the boards are too short they cannot be used. A
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Answer:

We conclude that the board's length is equal to 2564.0 millimeters.

Step-by-step explanation:

We are given that a sample of 26 is made, and it is found that they have a mean of 2559.5 millimeters with a standard deviation of 15.0.

Let \mu = <u><em>population mean length of the board</em></u>.

So, Null Hypothesis, H_0 : \mu = 2564.0 millimeters    {means that the board's length is equal to 2564.0 millimeters}

Alternate Hypothesis, H_A : \mu \neq 2564.0 millimeters      {means that the boards are either too long or too short}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                             T.S.  =  \frac{\bar X-\mu}{\frac{s }{\sqrt{n}} }  ~  t_n_-_1

where, \bar X = sample mean length of boards = 2559.5 millimeters

            s = sample standard deviation = 15.0 millimeters

             n = sample of boards = 26

So, <em><u>the test statistics</u></em> =  \frac{2559.5-2564.0}{\frac{15.0 }{\sqrt{26}} }  ~   t_2_5

                                     =  -1.529    

The value of t-test statistics is -1.529.

Now, at a 0.05 level of significance, the t table gives a critical value of -2.06 and 2.06 at 25 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so <u><em>we have insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the board's length is equal to 2564.0 millimeters.

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