Given two vectors a⃗ = 4.60 i^+ 7.20 j^ and b⃗ = 5.10 i^− 2.70 j^ , find the scalar product of the two vectors a⃗ and b⃗ .

1 answer:

6 0

A=<4.60,7.20>
b=<5.10,2.70>
The scalar product, or the inner product, or the dot-product, is by summing the products of the respective directions,
a.b=4.6*5.1+7.2*2.7
=23.46+19.44
=42.9

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Step-by-step explanation:

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$Given\ inequality\ y>x+10\\\\Ordered\ pair (a,b)\ satisfies\ the\ inequality\\\\Hence\ x=a,\ y=b\\\\Substitute\ these\ values\ in\ the\ inequality.\\\\b>a+10\\\\\Rightarrow b-a>10\\\\That\ means\ difference\ of\ b\ and\ a\ is\ greater\ than\ 10.$