Ask question

Ask question

All categories

3 years ago

5

a city known for it temperature extremes started the day at -5 degrees farenheit. the temperature increased by 78 degrees farenh

eit by midday and then dropped 32 degrees by nightfall

1 answer:

Zina [86]3 years ago

7 0

Temperature at nightfall = -5 + 78 - 32 = 41 degree Farenheit

You might be interested in

PLEASE HELP AND PLEASE SHOW YOUR WORKING

professor190 [17]

Answer:

S = 13 - x

T = (18 + x) / 2

Step-by-step explanation:

S = 18

T= 18

Sue gives away x, so subtract it from 18. But Tony gets x, so add it to 18 in his expression.

S = 18 - x

T= 18 + x

Sue eats 5 so subtract 5 from her expression. Tony eats half, so divide his expression by 2.

S = 18 - x - 5

T = 18 + x / 2

Simplify 18-5.

S = 13 - x

T = (18 + x) / 2

6 0

3 years ago

3×-y=5,2×+y=5 pleaseplease

Tanya [424]

Answer:

x = 2

y = 1

Step-by-step explanation:

3x - y = 5..............(1)× 1

2x + y = 5...….......(2)× 1

3x - y = 5..............(3)

2x + y = 5.............(4)

Cancel y

3x + 2x = 5 + 5

5x = 10

Divide both sides by 5

x = 2

Substitute for the value of y

3x - y = 5

3(2) - y = 5

6 - y = 5

6 - 5 = y

1 = y

y = 1

6 0

3 years ago

Which of the following sets are subspaces of R3 ?

Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

$\to A={(x,y,z)|3x+8y-5z=2} \\\\\to for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)$

The set A is not part of the subspace $R^3$

for point B:

$\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0$

$\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon B$

The set B is part of the subspace $R^3$

for point C: $\to C={(x,y,z)|x$

In this, the scalar multiplication can't behold

$\to for (-2,-1,2) \varepsilon C$

$\to -1(-2,-1,2)= (2,1,-1)$ ∉ C

this inequality is not hold

The set C is not a part of the subspace $R^3$

for point D:

$\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)$

The scalar multiplication s is not to hold

$\to for (-4, 1,2)\varepsilon D\\\\\to -1(-4,1,2) = (4,-1,-2)$ ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace $R^3$

For point E:

$\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\$

The $x_1, x_2$ is the arbitrary, in which $ax_1+bx_2$ is arbitrary

$\to a(x_1,0,0)+b(x_2,0,0) \varepsilon E$

The set E is the part of the subspace $R^3$

For point F:

$\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon F \\\\\to a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))$

The $x_1, x_2$ arbitrary so, they have $ax_1+bx_2$ as the arbitrary $\to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F$

The set F is the subspace of $R^3$

5 0

3 years ago

The perimeter of the square can be represented by the expression 36x+44 robin wants to write an equivalent expression for the pe

sukhopar [10]

Answer:

4 (9 x + 11) is an equivalent expression for the perimeter that shows the side length of the square is (9 x + 11).

Step-by-step explanation:

Here, given The perimeter of the square = (36 x+44)

Now,as we know :

PERIMETER OF SQUARE = 4 x ( SIDES)

Simplifying the perimeter expression.

Take 4 common out of the expression (36 x+44), we get:

(36 x+44) = 4 (9 x + 11)

⇒ Perimeter of the square = 4 x (9 x + 11)

⇒4 x ( SIDES) = 4 x (9 x + 11)

⇒ Each Side = (9 x + 11)

Hence, 4 x (9 x + 11) is an equivalent expression for the perimeter that shows the side length of the square is (9 x + 11).

5 0

3 years ago

Mr. Toler has a piece of wood that is 8 1/4 feet in length he wants to cut it into pieces that are three over 4 foot in length.

monitta

Answer:

11 pieces.Step-by-step explanation:We must divide 8 1/4 by 3/48 1/4 = 33/4Dividing:33/4 / 3/4= 33/4 * 4/3= 33/3= 11.

Step-by-step explanation:

11 pieces.Step-by-step explanation:We must divide 8 1/4 by 3/48 1/4 = 33/4Dividing:33/4 / 3/4= 33/4 * 4/3= 33/3= 11.

5 0

2 years ago