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BartSMP [9]
3 years ago
12

A drone is monitoring the atmospheric conditions above a farm field.

Mathematics
1 answer:
Viefleur [7K]3 years ago
4 0

Answer:

y=5 \ \ \ x x_o + 1.9s

Step-by-step explanation:

This situation can be considered as a piecewise function. First, you take xo as the time in which the drone goes upward. Before this time the height of the drone is constant with a value of 5 m. Next, you take into account that during 1.9 s after xo the drone accelerates. Finally, the drone flies again with a constant height of 5.9m. Hence, this function has three parts:

For the first part you have:

y = 5       for x <  xo

For the second part you first calculate vertical speed (which means the slope of the linear function) by using the following kinematic equation:

y=vx\\\\v=\frac{y-y_o}{x}=\frac{5.9m-5.0m}{1.9s}=0.47m/s

Then you have:

y = 0.47x    for xo < x < xo + 1.9s

And for the third part:

y = 5.9    for x > xo  + 1.9s

Summarizing you obtain:

y=5 \ \ \ x x_o + 1.9s

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Answer:

C.   40

Step-by-step explanation:

20 + 4x = 180

subtract 20 from both sides

4x = 160

Divide both sides by

x = 40

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3 years ago
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Answer:

The answer is (2,1)

Step-by-step explanation:

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3 years ago
1. If the product of the integers a,b, and c is 1, then what is the difference between the largest and the smallest possible val
Natali5045456 [20]
For question 1, the largest value would be 1 and the smallest value would be -1. A, B, and C are either all 1 or two is negative and one is positive, either way the number is 1 and it's opposite. 1^2 is 1, 1^3 is 1, 1^4 is 1. The product is 1. -1^2 is -1, -1^3 is -1, -1^4 is -1. The product is -1. Now the difference. 1 - (-1), which is 1 + 1, the answer is [D) 2]
4 0
3 years ago
The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac
olya-2409 [2.1K]

Answer:

a) \frac{74}{10025}

b) \frac{3x-2}{x(8x+1)}

c) \frac{-24x^2+32x-2}{(8x^2+x)^2}

Step-by-step explanation:

For total cost function c(x), average cost is given by \frac{c(x)}{x} i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., \left ( \frac{c(x)}{x} \right )'

Given:c(x)=\frac{3x-2}{8x+1}

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

a)

At x = 50 units,

\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}

b)

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

c)

Marginal average cost:

Differentiate average cost with respect to x

Take f=3x-2\,,\,g=8x^2+x

using quotient rule, \left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}

Therefore,

\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}

3 0
3 years ago
A seagull was flying about sea level looking to catch a fish below sea level. The elevation above sea level was 125 1/2 feet. He
frez [133]

Answer:

The seagull's position halfway is 85.5 feet.

Step-by-step explanation:

The seagull is at 125 1/2 feet above the sea level.

The fish is at 45 1/2 feet below the sea level.

The distance between the seagull and fish = seagull's distance above the sea level + fish's distance below the sea level

                                                  = 125 1/2 + 45 1/2

                                                  = \frac{251}{2} + \frac{91}{2}

                                                  = \frac{342}{2}

                                                  = 171

The distance between the seagull and fish is 171 feet.

Since the seagull stops halfway, then;

seagull's position = \frac{171}{2}

                             = 85.5

The seagull's position halfway is 85.5 feet.

8 0
2 years ago
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