
is the proportion of tires that are defective so

so we would expect around 1600 tires to be defective
The ratio for this problem is 1:5.
If you are drawing 14 pentagons, you would do 14 x 5.
14 (pentagons) x 5 (line segments) = 70 line segments in total.
The answer is C) 70
<span>3y^2 • 4x^2y • 5x = (3*4*5) * (</span><span>y^2 * y) * (</span><span>x^2*x) = 60 * y^3 * x^3 = 60 (xy)^3
</span>where ((<span>y^2 * y)) adding the powers in case of multiplication
and also for this:</span><span> (<span>x^2*x)</span> </span>
Answer:
600
Step-by-step explanation:
Given
equation t = 6n
n is term number
we have to find 100th term.
Thus, term number is 100
substituting 100 in place of n in equation t=6n , we can find the value of 100th term
t = 6*100 = 600
Thus, 100th term is 600.
Answer:
When increasing the radius 3 times the volume increases 9 times and when it is reduced to a third the volume decreases 9 times
Step-by-step explanation:
We have that the formula for the volume of a cone is:
Vc = pi * (r ^ 2) * h
We first calculate the original volume, where the radius is 2 and the height is 9, replacing:
Vc = 3.14 * (2 ^ 2) * 9
Vc = 113.04
Now if the radius is tripled it would be: 2 * 3 = 6, the radius would be 6, replacing:
Vc = 3.14 * (6 ^ 2) * 9
Vc = 1017.36
If we compare:
1017.36 / 113.04 = 9
This means that when the radius is tripled, the volume increases 9 times.
When if re reduces to a third the radius would be: 2/3, replacing:
Vc = 3.14 * ((2/3) ^ 2) * 9
Vc = 12.56
113.04 / 12.56 = 9
Which means that by reducing it to a third the volume becomes 9 times smaller.