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kobusy [5.1K]
3 years ago
5

Evaluate x(+3) (3+y). for x = 2, y = 5, and z = 1. pls help

Mathematics
2 answers:
mart [117]3 years ago
7 0

Answer

The answer is most likely 2 (or C).

Why?

The top of the question simplified into number is 2(5 + 3), which equals 16.

The bottom is (3 +5)1, which equals 8.

Now divide 16/8, which equals 2, and there's your answer.

(Hope this helps you! ^^)

pentagon [3]3 years ago
3 0

Answer:

2

Step-by-step explanation:

First, substitute the x’s and y’s:

2(5+3)/(3+5)1

since the one doesn’t make a difference, we don’t need to write it in.

2(5+3)/(3+5)

next, solve the parenthesis first:

5+3=8

3+5=8

so,

2(8)/8

Now since there are two 8s on each side, they cancel eachother out since if you cross them over and change the sign,

2/8/8

it equals 1.

so, you are left with 2.

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Answer: Answers are in the steps.

Step-by-step explanation:

The coefficients are 3, -5, and 1  

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3 years ago
What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36
GREYUIT [131]
ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

f(x) = {x}^{4} - 13 {x}^{2} + 36

To find the real roots, we equate the function to zero to obtain;

{x}^{4} - 13 {x}^{2} + 36 = 0

We can solve this equation as a quadratic equation in
{x}^{2}.

Thus we rewrite the equation as,

({x}^{2})^{2} - 13 {x}^{2} + 36 = 0

We split the middle term to get,

({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.

We factor to get,

{x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0

We factor to get,

( {x}^{2} - 9)( {x}^{2} - 4) = 0

Either

{x}^{2} - 9 = 0
or

{x}^{2} - 4 = 0

x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}
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The correct answer is A
5 0
4 years ago
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Answer:

y = 42

Step-by-step explanation:

Given that y varies directly as x then the equation relating them is

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To find k use an ordered pair from the table.

Using x = 2 when y = 12, then

12 = 2k ( divide both sides by 2 )

6 = k

y = 6x ← equation of variation

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Answer:

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Step-by-step explanation:

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