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Vlad [161]
3 years ago
11

3 - k - 5k =3 i need help on this asap

Mathematics
2 answers:
weeeeeb [17]3 years ago
8 0

Hello there!

3-k-5k=3

Combine like terms:

3-6k=3

-6k=3-3

-6k=0

k=0

Hope it helps!

~Just a determined gal

#CarryOnLearning

MysteriousNature

dimulka [17.4K]3 years ago
7 0

Answer:

k = 0

Step - By - Step:

1. 3 - k - 5k = 3

3 - 6k =3

2. rearrange terms:

3 - 6k = 3

-6k + 3 = 3

3. Subtract  3 from both sides of the equation:

-6k_3=3

-6k+3-3=3-3

4. simplify:

-6k + 3 - 3 = 3 - 3

-6k = 3 - 3

-6k = 0

5. divide both sides of the equation by the same term:

-6k = 0

-6k/-6 = 0/-6

6. simplify:

k = 0/-6

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Answer:

The linear equation relating price to demand is Q=-0.5*P + 30

Step-by-step explanation:

The demand for a good is the quantity of that good that the demanders are willing to purchase at a given price.

Then, the Demand Curve relates the quantity that a consumer would be willing to buy as a function of price.

You seek to determine the linear equation that relates the price to the demand Q = m * P + b where Q is the quantity demanded at a price P, and compared with the equation of the straight line y = mx + b, m is the slope and b is the ordinate to the origin.

On a line of the form y = m * x + b, the value of m, having two points, is calculated by:

m=\frac{y2-y1}{x2-x1}

And the ordinate to the origin b is calculated, taking the value of m, replacing any of the two points (replacing any of the two because it must give the same value of b) in the expression y = m * x + b and solving its value.

In the case of Q=m*P+b, the value of m, having two points, is calculated by:

m=\frac{Q2-Q1}{P2-P1}

Being:

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and replacing:

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you get:

m= -0.5

So, being Q=-0.5*P+b,  b is calculated by:

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5= -0.5*50 + b → 5= -25 + b → 5+25= b → b= 30

  • Replacing the point Q1= 10 and P1= 40

10= -0.5*40 + b → 10= -20 + b → 10+20= b → b= 30

Then, <u><em>the linear equation relating price to demand is Q=-0.5*P + 30</em></u>

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Step-by-step explanation:

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