1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sukhopar [10]
3 years ago
10

What is surface area?​

Mathematics
1 answer:
schepotkina [342]3 years ago
8 0
The surface area is the area of the outside of a 3D shape for example, let’s say you have a cube, a cube has 6 sides, so you have to find the area of each side and then add it up, since it’s a cube you would technically have to find the area of one side and then just multiply it by 6, that would be the easiest way to do it


Hope I helped!
You might be interested in
What is the answer to 3/4-3/8?
Norma-Jean [14]
6/8-3/8
3/8
the answer to 3/4-3/8 is 3/8
8 0
3 years ago
What is 5.6 = p - 8.3
vredina [299]

Answer:

p - 8.3 = 5.6

p = 5.6+8.3= 13.9

7 0
3 years ago
a regular rectangular pyramid has a base and lateral faces that are congruent equilateral triangles. it has a lateral surface ar
Margarita [4]
A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
(and the lateral edges of the pyramid are also equal to each other)

Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say x.

The lateral faces are equilateral triangles of side length x.

The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18  cm^2.

now we need to find x. Consider the picture attached, showing one lateral face of the pyramid.

by the Pythagorean theorem: 

h= \sqrt{ x^{2} - (x/2)^{2}}= \sqrt{ x^{2}- x^{2}/4}= \sqrt{3x^2/4}= \frac{ \sqrt{3} }{2}x

thus, 

Area_{triangle}= \frac{1}{2}\cdot base \cdot height\\\\18= \frac{1}{2}\cdot x \cdot \frac{ \sqrt{3} }{2}x\\\\ \frac{18 \cdot 4}{ \sqrt{3}}=x^2

thus:

x^2 =\frac{18 \cdot 4}{ \sqrt{3}}= \frac{18 \cdot 4 \cdot\  \sqrt{3} }{3}=24 \sqrt{3}       (cm^2)

but x^{2} is exactly the base area, since the base is a square of sidelength = x cm.


So, the total surface area = base area + lateral area =  24 \sqrt{3}+72   cm^2


Answer: 24 \sqrt{3}+72   cm^2

4 0
3 years ago
In the morning the temperature was -9°F The temperature increased by
Alexeev081 [22]

Answer:

16

Step-by-step explanation:

4 0
3 years ago
Divide 3/4 divided by 6
noname [10]

Answer: 1/8

░░░░░░░░░░░░░░░░░░░░░▄▀░░▌

░░░░░░░░░░░░░░░░░░░▄▀▐░░░▌

░░░░░░░░░░░░░░░░▄▀▀▒▐▒░░░▌

░░░░░▄▀▀▄░░░▄▄▀▀▒▒▒▒▌▒▒░░▌

░░░░▐▒░░░▀▄▀▒▒▒▒▒▒▒▒▒▒▒▒▒█

░░░░▌▒░░░░▒▀▄▒▒▒▒▒▒▒▒▒▒▒▒▒▀▄

░░░░▐▒░░░░░▒▒▒▒▒▒▒▒▒▌▒▐▒▒▒▒▒▀▄

░░░░▌▀▄░░▒▒▒▒▒▒▒▒▐▒▒▒▌▒▌▒▄▄▒▒▐

░░░▌▌▒▒▀▒▒▒▒▒▒▒▒▒▒▐▒▒▒▒▒█▄█▌▒▒▌

░▄▀▒▐▒▒▒▒▒▒▒▒▒▒▒▄▀█▌▒▒▒▒▒▀▀▒▒▐░░░▄

▀▒▒▒▒▌▒▒▒▒▒▒▒▄▒▐███▌▄▒▒▒▒▒▒▒▄▀▀▀▀

▒▒▒▒▒▐▒▒▒▒▒▄▀▒▒▒▀▀▀▒▒▒▒▄█▀░░▒▌▀▀▄▄

▒▒▒▒▒▒█▒▄▄▀▒▒▒▒▒▒▒▒▒▒▒░░▐▒▀▄▀▄░░░░▀

▒▒▒▒▒▒▒█▒▒▒▒▒▒▒▒▒▄▒▒▒▒▄▀▒▒▒▌░░▀▄

▒▒▒▒▒▒▒▒▀▄▒▒▒▒▒▒▒▒▀▀▀▀▒▒▒▄

7 0
3 years ago
Read 2 more answers
Other questions:
  • Nicole wants to know the height of a snow sculpture but it is too tall to measure. Nicole measured the shadow of the snow sculpt
    5·2 answers
  • Subtract and simplify: (y^2 - 7y - 5) - (-3y^2 + 3y - 4)
    6·2 answers
  • Passes through (1,-1) parallel to the line through (4,1) and (2,-3)
    15·1 answer
  • The graph of y = x2 is shown below.
    7·2 answers
  • The sum of two numbers is 58. The first number is 8 less than half the second number. Let c represent the first number. Let d re
    8·1 answer
  • If p and q prime number greater than 2which of the following is not even integer ? a.p+q b.p×q c.p^2-q^2 d.p-q​
    13·2 answers
  • what is the slope of the picture (if this is super easy, the reason I asked this question is that my brain is working horrible t
    7·1 answer
  • Monique rolls a six-sided number cube labeled 1 to 6.
    8·2 answers
  • Please help i dont understand it
    12·1 answer
  • a rectangular garden is 52m long and 34m broad a path 2m wide is running inside the garden calculate the cost of travelling the
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!