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3 years ago

a cell phone battery uses 1/3 of its charge in 3/8 of a day. How much charge will it use in one day?

1 answer:

3 0

$\bf \begin{array}{ccll}charge&day\\\cline{1-2}\frac{1}{3}&\frac{3}{8}\\\\x&1\end{array}\implies \cfrac{~~\frac{1}{3}~~}{x}=\cfrac{~~\frac{3}{8}~~}{1}\implies \cfrac{~~\frac{1}{3}~~}{\frac{x}{1}}=\cfrac{3}{8}\implies \cfrac{1}{3}\cdot \cfrac{1}{x}=\cfrac{3}{8}\\\\\\\cfrac{1}{3x}=\cfrac{3}{8}\implies 8=9x\implies \cfrac{8}{9}=x$

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Is X +3 a factor of 2X squared minus 2X -12

Fantom [35]

Answer: No, x+3 is not a factor of 2x^2-2x-12

========================================================

Explanation:

Let p(x) = 2x^2 - 2x - 12

If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).

Compare x+3 = x-(-3) to x-k to find that k = -3.

Plug x = -3 into the function

p(x) = 2x^2 - 2x - 12

p(-3) = 2(-3)^2 - 2(-3) - 12

p(-3) = 12

We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12

----------------------------------------

Let's see what happens when we factor p(x)

2x^2 - 2x - 12

2(x^2 - x - 6)

2(x - 3)(x + 2)

The factors here are 2, x-3 and x+2

3 0

3 years ago

Whoever answers correctly gets brainliest

ruslelena [56]

Here the answer in the image below as a table

C
D
E

6 0

3 years ago

Describe the transformation f(x) = 2x + 1 -> g(x) = -8(x + 4) - 1

katrin2010 [14]

f(x) = 2x + 1; Paren graph = x;

The graph was shifted one unit up and stretched 2 times.

g(x) = -8(x+4) - 1 = -8x - 32 - 1 = -8x - 33

The graph was shifted 33 units down and stretched 8 times and flipped 180 degrees.

8 0

3 years ago

mrs.beluga is driving on a snow covered road with a drag factor of 0.2. she brakes suddenly for a deer. The tires leave a yaw ma

Aneli [31]

First, we are going to find the radius of the yaw mark. To do that we are going to use the formula: $r= \frac{c^2}{8m} + \frac{m}{2}$
where
$c$ is the length of the chord
$m$ is the middle ordinate
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so $c=52$ and $m=6$ . Lets replace those values in our formula:
$r= \frac{52^2}{8(6)} + \frac{6}{2}$
$r= \frac{2704}{48} +3$
$r= \frac{169}{3} +3$
$r= \frac{178}{3}$

Next, to find the minimum speed, we are going to use the formula: $s= \sqrt{15fr}$
where
$f$ is <span>drag factor
</span> $r$ is the radius
We know form our problem that the drag factor is 0.2, so $f=0.2$ . We also know from our previous calculation that the radius is $\frac{178}{3}$ , so $r= \frac{178}{3}$ . Lets replace those values in our formula:
$s= \sqrt{(15)(0.2)( \frac{178}{3}) }$
$s= \sqrt{178}$
$s=13.34$ mph

We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was 13.34 miles per hour.

8 0

3 years ago

Which of the following is most likely the next step in the series

natima [27]

Answer:

Step-by-step explanation:

In the pattern, there are some similarities with the first three circles.

1. The number is on the blue half.

2. The halves switch spots, red-blue, blue-red, red-blue.

So, the next one should have the number on the blue half and the next pattern should be red-blue, blue-red, red-blue, and blue-red.

Which one has both the number on the blue half and the pattern blue-red?

Hoped this helped.

5 0

3 years ago

a cell phone battery uses 1/3 of its charge in 3/8 of a day. How much charge will it use in one day?​

a cell phone battery uses 1/3 of its charge in 3/8 of a day. How much charge will it use in one day?