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lidiya [134]
3 years ago
14

Which of the following is most likely the next step in the series

Mathematics
1 answer:
natima [27]3 years ago
5 0

Answer:

C

Step-by-step explanation:

In the pattern, there are some similarities with the first three circles.

1. The number is on the blue half.

2. The halves switch spots, red-blue, blue-red, red-blue.

So, the next one should have the number on the blue half and the next pattern should be red-blue, blue-red, red-blue, and blue-red.

Which one has both the number on the blue half and the pattern blue-red?

C

Hoped this helped.

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4 years ago
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0.051x40(0.5+0.01)x40 using distributive property
krek1111 [17]

Answer:

41.616

Step-by-step explanation:

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3 years ago
Select the correct answer.
gtnhenbr [62]

Answer:

5 years

Step-by-step explanation:

To determine the number of years needed for the company to process a certain amount of milk, we use the given function which relates the number of years, x, and the gallons of milk, y. We simply substitute the number of gallons to y and solve for x.  

y = x^6 − 9x^4 + 70x^2

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Solving for x, we will have

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Hope this answer helps you :)

Have a great day

Mark brainliest

7 0
3 years ago
Anyone know how to do area or volume? Any help will do! thanks
exis [7]

Answer:

Volume: x(x+6)(x+2) Area: x^{2} + 8x +12

Step-by-step explanation:

Volume Explanation:

To find the volume of a 3d figure, we must multiply the length, width, and the height. Therefore we multiply (x)(x+6)(x+2)= x^{3} + 8x^{2} + 12x. Simplify this equation and we will get x(x+6)(x+2) for the formula to find the volume of the 3D figure.

Area:

To find the area of a 2D figure, we must multiply length x height. Therefore, we multiply the equations (x+6)(x+2)= x^{2} + 2x + 6x +12 to get a final answer of x^{2} +8x +12.  This will be the formula when you find the area of the 2D figure in question.

7 0
2 years ago
Help me on this one i am stuck
dybincka [34]
8/20as well,since the number of green beads and yellow beads is the same,so equal probability
8 0
2 years ago
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