How do I change my profile picture, plz answer.

Mathematics

2 answers:

tatiyna3 years ago

8 0

Answer:

Assuming you're on mobile, press "Me" at the bottom, and then at the top there will be your default profile pic, and then click that, and then press the + button and choose your desired picture.

zaharov [31]3 years ago

6 0

Answer:

got to settings

Step-by-step explanation:

You might be interested in

The Perimeter Of A Rectanglular Garden Is 84 Feet . The Length Of The Garden Is Twice The Width . What Is The Width Of The Garde

nalin [4]

$\bf \stackrel{\textit{perimeter of a rectangle}}{P=2L+2W\implies 2(L+W)}~~
\begin{cases}
L=length\\
W=width\\
--------\\
P=84\\
L=\stackrel{\textit{twice the width}}{2W}
\end{cases}
\\\\\\
84=2(L+W)\implies \cfrac{84}{2}=L+W\implies 42=L+W
\\\\\\
42=(2W)+W\implies 42=3W\implies \cfrac{42}{3}=W\implies 14=W$

5 0

3 years ago

Ex 7) Imagine a mile-long bar of metal such as the rail along railroad tracks. Suppose that the rail is anchored on both ends an

Fantom [35]

9514 1404 393

Answer:

about 44.5 feet

Step-by-step explanation:

We can write relations for the height of the rail as a function of initial length and expanded length, but the solution cannot be found algebraically. A graphical solution or iterative solution is possible.

Referring to the figure in the second attachment, we can write a relation between the angle value α and the height of the circular arc as ...

h = c·tan(α) . . . . . . where c = half the initial rail length

Then the length of the expanded rail is ...

s = r(2α) = (c/sin(2α)(2α) . . . . . . where s = half the expanded rail length

Rearranging this last equation, we have ...

sin(2α)/(2α) = c/s

It is this equation that must be solved iteratively. We find the solution to be ...

α ≈ 0.0168538794049 radians

So, the height of the circular arc is ...

h = 2640.5·tan(0.0168538794049) ≈ 44.4984550191 . . . feet

The rail will bow upward by about 44.5 feet.

_____

<em>Additional comments</em>

Note that s and c in the diagram are half the lengths of the arc and the chord, respectively. The ratio of half-lengths is the same as the ratio of full lengths: c/s = 2640/2640.5 = 5280/5281.

We don't know the precise shape the arc will take, but we suspect is is not a circular arc. It seems likely to be a catenary, or something similar.

We used Newton's method iteration to refine the estimate of the angle from that shown on the graph. The iterator used is x' = x -f(x)/f'(x), where x' is the next guess based on the previous guess of x. Only a few iterations are required obtain an angle value to full calculator precision.