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marysya [2.9K]
2 years ago
14

Is 0.3478 a rational number

Mathematics
1 answer:
Sav [38]2 years ago
5 0

Answer:

yes

Step-by-step explanation:

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Will mark as Brainlist
Semmy [17]

The answer :

4/5

Step-by-step explanation:

4x-5y=0  

subtract 4x on both the sides  

4x-4x-5y = 0-4x  

-5y = -4x

divide by -5 on both the sides  

-5y/-5 = -4x/-5

y =( 4/5 )x  

4 0
3 years ago
30 pts + BRAINLIEST
ivanzaharov [21]

Answer:

Number of permutations = 5040

Step-by-step explanation:

We are given the word 'INNOVATIVE', that has total 10 letters.

Now, we are asked to form words using exactly 4 letters at a time i.e. out of 10 letters we are using 4.

Therefore, the number of permutations that can be formed using 4 letters are = P(10,4)

i.e. 10_{P_{4} }

= \frac{10!}{(10-4)!}

= \frac{10!}{6!}

= \frac{10*9*8*7*6!}{6!}

= 10*9*8*7

= 5040

8 0
3 years ago
Read 2 more answers
Find 3/5 - 1/4 <br><br> a 4/9<br><br> b 1/2<br><br> c 2<br><br> d 7/20
Lubov Fominskaja [6]

Answer:

7/20

Step-by-step explanation:

Hope this helped!

7 0
3 years ago
Read 2 more answers
LK is tangent to circle J at point K. Circle J is shown. Line segment J K is a radius. Line segment K L is a tangent that inters
Evgen [1.6K]

Answer:

(B)r=\dfrac{85}{12}

Step-by-step explanation:

Given a circle centre J

Let the radius of the circle =r

LK is tangent to circle J at point K

From the diagram attached

  • LX=6
  • Radius, XJ=JK=r
  • LK=11

Theorem: The angle between a tangent and a radius is 90 degrees.

By the theorem above, Triangle JLK forms a right triangle with LJ as the hypotenuse.

Using Pythagoras Theorem:

(6+r)^2=r^2+11^2\\(6+r)(6+r)=r^2+121\\36+6r+6r+r^2=r^2+121\\12r=121-36\\12r=85\\r=\dfrac{85}{12}

The length of the radius, r=\dfrac{85}{12}

8 0
3 years ago
Read 2 more answers
What is the common difference between the terms in the following sequence?
Sergeeva-Olga [200]

Answer:

  -6

Step-by-step explanation:

Take a couple of differences and see:

  11 -17 = -6

  5 -11 = -6

The common difference is -6.

8 0
3 years ago
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