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maksim [4K]
3 years ago
8

Which equation yields the solutions x=−3 and x=−4?

Mathematics
1 answer:
Elza [17]3 years ago
5 0

Answer:

a) 2x² + 14x + 24 = 0

Step-by-step explanation:

a)

2x² + 14x + 24 = 0

2(x + 4) (x + 3) = 0

x = -4 or x = -3

b)

x² - 6x + 5 = 0

(x - 1)(x - 5) = 0

x = 1 or x = 5

c)

3x² + 30x + 48 = 0

3 (x + 8) (x + 2) = 0

x = -8 or x = -2

d)

-3x² - 12x + 15 = 0

-3 (x + 5) (x - 1) = 0

x = -5 or x = 1

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Carl and Stephen and Brittney completed in a shot put competition .Stephen's toss was 4.08 feet farther than Brittney's. Carl's
Lemur [1.5K]

Answer:

R4ARAQuestion

Carl and Stephen and Brittney completed inQuestion

Carl and Stephen and Brittney completed in a shot put competition .Stephen's toss was 4.08 feet farther than Brittney's. Carl's toss was 2.14 shorter then Stephen's ​ a shot put competition .Stephen's toss was 4.08 feet farther than Brittney's. Carl's toss was 2.14 shorter then Stephen's ​RARRARAGG

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The graph of an equation is shown below:
ziro4ka [17]

Answer:

The point   (1,3) is a solution of the linear equation

Step-by-step explanation:

we have

A(-3,-2)\ B(1,3)

<u>Find the equation of the line AB</u>

The slope of the line is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values

m=\frac{3+2}{1+3}

m=\frac{5}{4}

Find the equation of the into point-slope form

y-y1=m(x-x1)

we have

m=\frac{5}{4}

(x1,y1)=B(1,3)

substitute

y-3=\frac{5}{4}(x-1)

we know that

If a point is a solution to the equation of the line

then

the point must be satisfy the equation and based on the graph the point must be on the line

Let's check every point.

<u>case A)</u> point (-2,-3)

Substitute the value of x and y in the equation of the line

-3-3=\frac{5}{4}(-2-1)

-6=-\frac{15}{4} -------> is not true

The point  (-2,-3) is not a solution of the linear equation

See the attached figure-------> the point is not on the line

<u>case B)</u> point (3,1)

Substitute the value of x and y in the equation of the line

1-3=\frac{5}{4}(3-1)

-2=\frac{10}{4} -------> is not true

The point   (3,1) is not a solution of the linear equation

See the attached figure-------> the point is not on the line

<u>case C)</u> point (1,3)

Substitute the value of x and y in the equation of the line

3-3=\frac{5}{4}(1-1)

0=0 -------> is  true

The point   (1,3) is a solution of the linear equation

See the attached figure-------> the point is on the line

<u>case D)</u> point (3,2)

Substitute the value of x and y in the equation of the line

2-3=\frac{5}{4}(3-1)

-1=\frac{10}{4} -------> is not true

The point   (3,2) is not a solution of the linear equation

See the attached figure-------> the point is not on the line

8 0
3 years ago
What is the slope of the line that passes through the points (2, 3) <br> and (–2, 6)?
saw5 [17]
Slope = (6 - 3)/(-2-2)
= 3/-4
= -3/4

answer
slope = -3/4
4 0
3 years ago
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Need help finding out what 3x=y and x-2y = 10
sweet-ann [11.9K]

Answer:

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Step-by-step explanation:

Simple substitution.

Since y is isolated in one of the equations already, you can plug it into the second equation.

x - 2(3x) = 10

x - 6x = 10

-5x = 10

x = -2

Sub. x = -2 into 3x = y:

3(-2) = y

y = -6

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dusya [7]
9 because when you subtract the amount of poster money from the total ($19.35), you get $14.85. $14.85 divided by $1.65 is 9, which means he bought 9 notebooks.
4 0
3 years ago
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