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goldenfox [79]
3 years ago
14

Taylor has 16 tacks. she buys 2 packages of 36 tacks. how many gate sale posters can she put up if she uses 4 tacks for each pos

ter?
Mathematics
1 answer:
Gemiola [76]3 years ago
4 0


She can Hang up 4 posters. Because Taylor only has 16 tacks.

16/4=4

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The probability that Hank Aaron hits a home run on any given at-bat is 0.14, and
Liula [17]

Answer:

Step-by-step explanation:

3 0
3 years ago
Find the area of the following shape. (8 points)<br><br> what is the answer?
Ivenika [448]

Answer:

72 square units

Step-by-step explanation:

  1. Identify the height
  2. Identify the length
  3. Multiply those two together
  4. That is your answer

H = 9 units

L = 8 units

A = H × L

A = 9 × 8

A = 72 square units

8 0
2 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
Find the measure of angle BEC.
liubo4ka [24]

Answer:

∠BEC=180°-94° = 86° ig

4 0
2 years ago
How would I solve this
Feliz [49]
What are you solving for???
3 0
3 years ago
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