Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
5 is the answer
I used my phone
Original Perimeter = 2.5 + 2.5 + 1.5 + 1.5 = 8
The longer dimension is 2.5 as 2.5 > 1.5To make 2.5 into 10, we must multiply by 4For the smaller length, we must also multiply by 41.5 x 4 = 6
New Perimeter = 10 + 10 + 6 + 6 = 32
Now find the difference between the old and the new perimeter32 - 8 = 24
<em>*No units were specified - if included, remember to put them in your answer.</em>
THE WHOLE THING???? or just one answer?
