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I am Lyosha [343]
4 years ago
13

Does anyone know this ? Please .

Mathematics
2 answers:
hoa [83]4 years ago
6 0

Answer:

5/4 hope this helps

Step-by-step explanation:

Korvikt [17]4 years ago
3 0

ANSWER

The correct answer is D.

EXPLANATION

The given exponentiial expression is

{5}^{ \frac{7}{3} }

Recall that:

{a}^{ \frac{m}{n} }  =  \sqrt[n]{ {a}^{m} }

We put a=5, n=3 and m=7

This implies that,

{5}^{ \frac{7}{3} }  =  \sqrt[3]{ {5}^{7} }

The correct answer is D.

The last option is correct.

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Simplify (3x + 5) + (2x-9) - 14
zalisa [80]

Answer:

<h2>5x-18</h2>

Step-by-step explanation:

lets simplify!

(3x+5)+(2x-9)-14

combine like terms..

5x+ -4 - 14

subtract numbers without exponents

therefore, the answer is

5x-18

hope this helps:)

6 0
4 years ago
Solve this problem. Reduce to lowest terms.
Pepsi [2]
4 3/4 + 2 1/2 = 4 3/4 + 2 2/4 = 6 5/4 = 7 1/4 = 6 hours and 15 minutes.
6 0
4 years ago
Can anyone solve this?
UkoKoshka [18]

Answer:

D) 26.04 ft

Step-by-step explanation:

Let's set up a equation with two ratios:

\frac{miniature\ house}{real\ house}=\frac{miniature\ house}{real \ house}

Plug in the given lengths into the equation:

\frac{1in}{1.55ft}=\frac{16.8in}{x}

We can solve this using cross multiplication (multiply the numerator of the first fraction by the denominator of the second and the numerator of the second by the denominator of the first):

1x=16.8*1.55\\1x=26.04

D) 26.04 ft

6 0
3 years ago
Read 2 more answers
A building 30 feet tall casts a shadow 20 feet long. A person 6 feet tall is walking directly away from the building toward the
DIA [1.3K]

Answer:

  16 feet

Step-by-step explanation:

The shadow is 20/30 = 2/3 the length of the object, so the 6-foot person's shadow will be 4 ft long. It will begin to emerge when the person is 4 feet from the tip of the building's shadow. That distance is ...

  20 ft - 4 ft = 16 ft

from the building.

3 0
4 years ago
PLEASEE HELP MEEE
Thepotemich [5.8K]
The task is to find the original coordinates with the transformed ones given, so you have to apply the inverse of the stated transformations.

Q"( 6,-1),R"(0,-1) and S"(0,-7)
-> rotate 90 anti-clockwise
Q'(1,6), R'(1,0),S'(7,0)
-> translate left by 7 units
Q(-6,6), R(-6,0), S(0,0)
3 0
4 years ago
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