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saw5 [17]
3 years ago
10

0.6(4-2x)=20.5-(3x+10)

Mathematics
1 answer:
solong [7]3 years ago
5 0

The solution of 0.6(4-2x)=20.5-(3x+10) is x = 4.5

<u>Solution:</u>

Given, expression is 0.6 ( 4 – 2x ) = 20.5 – ( 3x + 10 )

We have to solve the above given equation for x.

Now, take the equation  

\rightarrow 0.6(4-2 x)=20.5-(3 x+10)

We have to use BODMAS rule. BODMAS means sequence of operations which is brackets, order, division, multiplication, addition and then subtraction

On solving the brackets, we get

\rightarrow 0.6 \times 4-0.6 \times 2 x=20.5-3 x-10

Now multiplication is given preference

\rightarrow 2.4-1.2 x=10.5-3 x

\rightarrow 3 x-1.2 x=10.5-2.4

Now subtraction is done

\rightarrow 1.8 \mathrm{x}=8.1

Now division is performed

\rightarrow x=\frac{8.1}{1.8}=4.5

Hence, the value of x is 4.5

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Step-by-step explanation:

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4 0
3 years ago
For safety reasons, 4 different alarm systems were installed in the vault containing the safety deposit boxes at a Beverly Hills
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Answer:

<em>99.93%</em>

Step-by-step explanation:

<u>Probability of Independent Events</u>

Given the probability of success of each detector is 0.84 independently of the others, their combined success/failure probability can be computed with the product rule.

We can calculate the required probability by using the binomial distribution, but it's easier to calculate the probability of the negated event an subtract from 1.

We want to know the probability that a least one of the 4 systems detects the occurrence of theft. That probability is the sum of the probabilities that one of them, two of them, three of them or all of them succeed. The negated event is that NONE of them actually detects the theft. Being p the individual probability of success, p=0.84. Being q the probability of failure, q=0.16.

The probability that none of the systems detect the theft is

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3 0
3 years ago
I will mark you the brainiest for the correct answer, please be correct, Have a good day and take care, thanks. ( VIEW THE IMAGE
makkiz [27]

Mistake in Line 2 : Was in the determining the values for a ,b,c

Mistake in Line 4 : Not taking the square roots of both sides.

Step-by-step explanation:

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First Mistake : Line 2

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Second Mistake : Line 4

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