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snow_tiger [21]

2 years ago

12

There are three times as many girls as boys in the school choir. If there are 24 girls how many singers are in the chior altoget

her

2 answers:

Goshia [24]2 years ago

8 0

Answer:

chicken

Step-by-step explanation:

nugget

BaLLatris [955]2 years ago

4 0

Answer: 8

Step-by-step explanation:

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The average of 8 numbers is 10. the average of 6 of the numbers is 12 what is the average of the other 2 numbers

omeli [17]

So, all 8 numbers added up would equal 80. and all 6 numbers added up would equal 72. The subtract them. 80-72 is 8. Then divide by 2 because there are 2 numbers. 8/2 is 4. (4 is your answer)

7 0

3 years ago

What is the solution to 9x−6<21?

OverLord2011 [107]

Answer:

x < 3

Step-by-step explanation:

Solve it like a normal equation

Isolate the variable along with its constant

9x - 6 + 6< 21 + 6

9x < 27

Isolate the variable its self

9x/9 < 27/9

x < 3

<h2>REMEMBER : ONLY FLIP THE INEQUALITY SIGN WHEN <u>MULTIPLYING</u> OR <u>DIVIDING</u> BY A <u>NEGATIVE NUMBER</u></h2>

7 0

3 years ago

A prticular type of tennis racket comes in a midsize versionand an oversize version. sixty percent of all customers at acertain

svetlana [45]

Answer:

a) P(x≥6)=0.633

b) P(4≤x≤8)=0.8989 (one standard deviation from the mean).

c) P(x≤7)=0.8328

Step-by-step explanation:

a) We can model this a binomial experiment. The probability of success p is the proportion of customers that prefer the oversize version (p=0.60).

The number of trials is n=10, as they select 10 randomly customers.

We have to calculate the probability that at least 6 out of 10 prefer the oversize version.

This can be calculated using the binomial expression:

$P(x\geq6)=\sum_{k=6}^{10}P(k)=P(6)+P(7)+P(8)+P(9)+P(10)\\\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\geq6)=0.2508+0.215+0.1209+0.0403+0.006=0.633$

b) We first have to calculate the standard deviation from the mean of the binomial distribution. This is expressed as:

$\sigma=\sqrt{np(1-p)}=\sqrt{10*0.6*0.4}=\sqrt{2.4}=1.55$

The mean of this distribution is:

$\mu=np=10*0.6=6$

As this is a discrete distribution, we have to use integer values for the random variable. We will approximate both values for the bound of the interval.

$LL=\mu-\sigma=6-1.55=4.45\approx4\\\\UL=\mu+\sigma=6+1.55=7.55\approx8$

The probability of having between 4 and 8 customers choosing the oversize version is:

$P(4\leq x\leq 8)=\sum_{k=4}^8P(k)=P(4)+P(5)+P(6)+P(7)+P(8)\\\\\\P(x=4) = \binom{10}{4} p^{4}q^{6}=210*0.1296*0.0041=0.1115\\\\P(x=5) = \binom{10}{5} p^{5}q^{5}=252*0.0778*0.0102=0.2007\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\\\P(4\leq x\leq 8)=0.1115+0.2007+0.2508+0.215+0.1209=0.8989$

c. The probability that all of the next ten customers who want this racket can get the version they want from current stock means that at most 7 customers pick the oversize version.

Then, we have to calculate P(x≤7). We will, for simplicity, calculate this probability substracting P(x>7) from 1.

$P(x\leq7)=1-\sum_{k=8}^{10}P(k)=1-(P(8)+P(9)+P(10))\\\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\leq 7)=1-(0.1209+0.0403+0.006)=1-0.1672=0.8328$

7 0

3 years ago

The shape below is transformed to another shape.

netineya [11]

Answer:

Option 4 is the image of the given figure.

Step-by-step explanation:

We are given that,

The shape EFGHCD is transformed to form another shape.

From the options, we see that,

Figure 2 and 3 does not have the same vertices as that of the figure.

So, they are discarded.

Since, after transforming a figure, we get a new figure.

So, the vertices cannot have same name as that of the original figure.

So, option 1 is discarded.

Thus, we get,

Option 4 is the image of the given figure after transformation as shown below.

5 0

3 years ago

Read 2 more answers

Solve the problem below, simplify, add steps<br> 1/3 √21 minus 2/3 √3 * √7

iogann1982 [59]

Do you want square root? And If so then here is the answer:Rewrite <span><span>√37</span>37</span> as <span><span>√3√7</span>37</span>.<span><span>√3√7</span>37</span>Multiply <span><span>√3√7</span>37</span> by <span><span>√7√7</span>77</span>.<span><span><span>√3√7</span><span>√7√7</span></span><span>37⁢77</span></span>Simplify. And in the end of, this I put the decimals.√<span><span>217</span><span>217</span></span>The result can be shown in both exact and decimal forms.Exact Form:<span><span><span>√21</span>7</span></span>Decimal Form:<span>0.65465367<span>… not sure this answer.
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4 0

3 years ago