Ask question

Ask question

All categories

3 years ago

13

Mauricio conducted an experiment in which he drew marbles out of the bag and recorded the colors. The results of the experiment

are shown in the table above. What is the probability that Mauricio drew a yellow marble?

2 answers:

stellarik [79]3 years ago

5 0

Answer:

The area of blue is greater than area of pink.

Step-by-step explanation:

Rzqust [24]3 years ago

3 0

60 to 14 would be the answer I think.

You might be interested in

Duc has a trapezoid shaped section of his yard fenced off for his pets. The lengths of the parallel sides of the trapezoid are 8

posledela

The area is equal to 44 ft.

Hope this answer helps!

7 0

3 years ago

Read 2 more answers

Find the greatest common factor of 10, 7, and 14.

SOVA2 [1]

Answer:

there is none

Step-by-step explanation:

7 is a prime number. the gcf of 10 and 14 is 2, but the only factors of 7 are 1 and 7

8 0

3 years ago

Read 2 more answers

The time between arrivals of customers at the drive-up window of a bank follows an exponential probability distribution with a m

castortr0y [4]

Answer:

a) 50.34% probability that the arrival time between customers will be 7 minutes or less.

b) 24.42% probability that the arrival time between customers will be between 3 and 7 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 10 minutes:

This means that $m = 10, \mu = \frac{1}{10} = 0.1$

A. What is the probability that the arrival time between customers will be 7 minutes or less?

$P(X \leq x) = 1 - e^{-\mu x}$

$P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034$

50.34% probability that the arrival time between customers will be 7 minutes or less.

B. What is the probability that the arrival time between customers will be between 3 and 7 minutes?

$P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3)$

$P(X \leq x) = 1 - e^{-\mu x}$

$P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034$

$P(X \leq 3) = 1 - e^{-0.1*3} = 0.2592$

$P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3) = 0.5034 - 0.2592 = 0.2442$

24.42% probability that the arrival time between customers will be between 3 and 7 minutes

3 0

3 years ago

A students work to solve 2 6/7 / 2/7 is shown below.

Alexus [3.1K]

A) the only mistake is changing the mixed number to an improper fraction .

6 0

3 years ago

Read 2 more answers

A jewelry shop sells 240 necklaces in a month.

zhuklara [117]

Answer:3 to 2

Step-by-step explanation:

5 0

3 years ago