ΔABC is a 45 - 45 - 90 triangle. The pattern of its sides is as follows:
Each leg = 1 unit (and both legs are that way, since the triangle is isosceles - so two sides are the same)
Hypotenuse = √2 units.
So if we know either leg, we multiply by √2 to get the hypotenuse. In reverse, we divide by √2 if we know the hypotenuse to get the measurement of a leg.
Our problem tells us that the hypotenuse AC is 10 units. We divide 10 by √2 to get the measurement of leg AB. Since it's a 45 -45 - 90 triangle, AB = BC.

to rationalize the radical

Thus, each leg is 5\sqrt{2} [/tex].
The answer is 6 cm. The mid segment is half of BC
For this case the first thing you should do is observe that the diameter of the four semicircles is the same.
Therefore, we can decompose the figure as follows:
1) We draw the diameters of the four semicircles to form a square.
2) We divide the figure into a square and four semicircles
3) The total area is the sum of the area of the square, plus the area of the 4 semicircles.
Answer:
c)as a square and four semicircles