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vlada-n [284]
3 years ago
5

In the first step, 4-sulfanilic acid reacts with sodium nitrate to form diazonium ion intermediate. Identify the Lewis acid and

Lewis base in this reaction.
Chemistry
1 answer:
Ainat [17]3 years ago
5 0

Answer:

In the formation of diazonium ion intermediate, the <em><u>4-sulfanilic acid acts as the Lewis acid</u></em>, while the <em><u>sodium nitrite is the Lewis base.</u></em>

Explanation:

A Lewis acid is by definition an electron pair acceptor (such as the H+ ion, that can accept a pair of non-bonding electrons) and a Lewis base is an electron pair donor (such as the OH- ion, that can donate a pair of non-bonding electrons).

In the formation of diazonium ion intermediate, the 4-sulfanilic acid acts as the Lewis acid(by transference of a lone pair from its nitrogen atom), while the sodium nitrite is the Lewis base.

<em>N.B </em><em>its sodium nitrite, NaNO2 (which is slightly basic in solution) not nitrate NaNO3 (which is neutral in solution)</em>

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3 years ago
Calculate the concentration of oxalate ion (c2o42–) in a 0.175 m solution of oxalic acid (c2h2o4). [for oxalic acid, ka1 = 6.5 ×
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