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3 years ago

2. Based on the following balanced equation:

1 answer:

7 0

To do this, just take the given miles and multiply it with the ratio of molecules in the chemical equation to get your answer.

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HC2H3O2 (aq) + H2O (l) ⇔ C2H3O2- (aq) + H3O+ (aq) Ka = 1.8 x 10-5

marin [14]

The concentration of [H3O⁺]=2.86 x 10⁻⁶ M

<h3>Further explanation</h3>

In general, the weak acid ionization reaction

HA (aq) ---> H⁺ (aq) + A⁻ (aq)

Ka's value

$\large {\boxed {\bold {Ka \: = \: \frac {[H ^ +] [A ^ -]} {[HA]}}}}$

Reaction

HC₂H₃O₂ (aq) + H₂O (l) ⇔ (aq) + H₃O⁺ (aq) Ka = 1.8 x 10⁻⁵

$\tt Ka=\dfrac{[C_2H_3O^{2-}[H_3O^+]]}{[HC_2H_3O_2]}}\\\\1.8\times 10^{-5}=\dfrac{0.22\times [H_3O^+]}{0.035}$

[H₃O⁺]=2.86 x 10⁻⁶ M

5 0

3 years ago

50 PONITS TO RIGHT AWNSERS!!!

Ivan

Distance and period of time is the correct answer

Hope this helps!

7 0

3 years ago

Read 2 more answers

? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2

Novay_Z [31]

Data:
$M_{concentrated} = 2.5\:mol$
$V_{concentrated} = ?$
$M_{dilute} = 0.50\:mol$
$V_{dilute} = 100\:mL\to0.100\:L$
<span>
Formula: Dilution Calculations

</span> $M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}$
<span>
Solving:

</span>
$M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}$
$2.5 * V_{concentrated} = 0.50 * 0.100$
$2.5V_{concentrated} = 0.05$
$V_{concentrated} = \frac{0.05}{2.5}$
$\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark$ <span>

</span>

3 0

4 years ago

Kendra conducts an experiment. She mixes two chemicals, resulting in a chemical reaction. Based on Kendra's

kondaur [170]

Answer: It changed in identity and properties.

Explanation:

3 0

3 years ago

If the empirical formula of a compound is CH2, which of the following could be a possible molecular formula for this

DiKsa [7]

Answer:

C2H2

Explanation:

8 0

3 years ago