<span>m∠CED = </span><span>1/2(m∠AOB + </span><span><span>m∠COD)</span> = 1/2(90° + 16°) = 1/2(106°) = 53°</span>
Answer:
B
Step-by-step explanation:
45-45-90
find hypotenuse: leg × root 2
10.5 hours
let t be time then distance travelled by both is
Mr Burges ⇔ d = 50t ( distance = speed × time )
Mrs Burges ⇒ d = 70(t - 3)
At the point of overtaking both will have travelled the same distance
equating their distance and solving for t
70(t - 3) = 50t
70t - 210 = 50t ( subtract 50t from both sides )
20t - 210 = 0 ( add 210 to both sides )
20t = 210 ( divide both sides by 20 )
t = 10.5 hours
<h2>
Answer:</h2><h2> hey are you army</h2>
Step-by-step explanation:
<h2>hiii army</h2>
Note on how to solve such equation:
This is a quadradic equation. The figure shown is a parabola. This parabola opens downward. Now, this information is not necessary important for this particular situation; however, it needs to be retained for said class or for the near future.
The equation for a quadradic function is: f(x)=x^2+2
when x=-2, y=1
