Let's call :
x=the number of downloaded standard version
y= the number of downloaded high-quality version
We have : -the high-quality version was downloaded three times as often as the
standard version => 3x=y
-standard version is 2.8 megabytes .the high-quality version is 4.6
MB.The total size downloaded for the two versions was 4482 MB
=> 2.8x+4.6y=4482
Solve for x,y
x=270 , y=810
Answer:
75% (sorry if Im wrong)
Step-by-step explanation:
If your taking a 50% discount off the original number your left with half, correct. If you take another 50% of thats 25% of the original number. you took more than 50% off and less than 100%, so 75%.
Answer:
a) 3⁵5³.
b) 1
c) 23³
d) 41·43·53
e) 1
f) 1111
Step-by-step explanation:
The greatest common divisor of two integers is the product of their common powers of primes with greatest exponent.
For example, to find gcd of 2⁵3⁴5⁸ and 3⁶5²7⁹ we first identify the common powers of primes, these are powers of 3 and powers of 5. The greatest power of 3 that divides both integers is 3⁴ and the greatest power if 5 that divides both integers is 5², then the gcd is 3⁴5².
a) The greatest common prime powers of 3⁷5³7³ and 2²3⁵5⁹ are 3⁵ and 5³ so their gcd is 3⁵5³.
b) 11·13·17 and 2⁹3⁷5⁵7³ have no common prime powers so their gcd is 1
c) The only greatest common power of 23³ and 23⁷ is 23³, so 23³ is the gcd.
d) The numbers 41·43·53 and 41·43·53 are equal. They both divide themselves (and the greatest divisor of a positive integer is itself) then the gcd is 41·43·53
e) 3³5⁷ and 2²7² have no common prime divisors, so their gcd is 1.
f) 0 is divisible by any integer, in particular, 1111 divides 0 (1111·0=0). Then 1111 is the gcd
Answer:
(x + 4)² + (y - 9)² = 25
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
here (h, k) = (- 4, 9) and r = 10 ÷ 2 = 5, thus
(x - (- 4))² + (y - 9)² = 5², that is
(x + 4)² + (y - 9)² = 25
.83% is the answer osdndksnsjfbbdbddh
