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Keith_Richards [23]
3 years ago
14

,s.richards gave her class minutes to read. alex read 9 1/3 pages in that time. At this rate, how many pages will alex read per

hour?
Mathematics
1 answer:
IgorC [24]3 years ago
5 0

Answer:

\dfrac{560}{t} pages per hour.

given that t is the amount of time gives her class to read.

Step-by-step explanation:

It isn't stated that exactly how many minutes the teacher gave Alex to read.

So to go further with this solution, we'll say that the teacher gave t minutes reading time to each student. (so you can just replace t with the actual  number in your answer)

Alex read 9\frac{1}{3}[tex] pages in [tex]t minutes.

by dividing the pages with the time, we'll find the rate of pages at which Alex reads per minute.

9\frac{1}{3} \div t

we can simplify the mixed fraction

\dfrac{28}{3} \times \dfrac{1}{t}

\dfrac{28}{3t} \frac{\text{pages}}{\text{minute}}  (Alex's speed)

To find out how many page Alex will read in an hour we can simply convert the minutes to hour by multiplying by 60 minutes.

\dfrac{28}{3t} \frac{\text{pages}}{\text{minute}} \times \frac{\text{60 minute}}{\text{hour}}

we can see that the minutes cancel out. and 60 multiplies with 28.

\dfrac{1680}{3t} \frac{\text{pages}}{\text{hour}}

\dfrac{560}{t} \frac{\text{pages}}{\text{hour}}

this shows that Alex read \dfrac{560}{t} pages per hour.

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A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the
Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{1}{455} = 0.0021

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{36}{455} = 0.0791

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

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Replacing terms:

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Answer:

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Step-by-step explanation:

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The error of his estimate in miles can be calculated as the difference between his estimate and the real outcome:

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To calculate the error as a percent, we divide that quantity by the original estimate and multiply by 100%:

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Rounding to the nearest hundredth:

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