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Brilliant_brown [7]

3 years ago

15

One kind of candy (jelly) sells for $5 a pound and another (chocolate) for $10 a pound. How many pounds of each should be used t

o make a mixture of 10 pounds of candy (both kinds) that sells for a total $80 (i.e. $8/pound)?

1 answer:

Vanyuwa [196]3 years ago

5 0

Answer:

chocolate: 6 pounds
jelly: 4 pounds

Step-by-step explanation:

Let x represent the number of pounds of chocolate in the mix. Then the total price of 10 pounds of mix is ...

10x +5(10 -x) = 80

5x +50 = 80

5x = 30

x = 6 . . . . . . . . pounds of chocolate

10 -x = 4 . . . . . pounds of jelly candy

6 pounds of chocolate and 4 pounds of jelly should be used to make the mixture.

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Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

7 0

3 years ago

HELP PLEASE! Thank you

Lostsunrise [7]

Answer:

2000

Step-by-step explanation:

Hello,

A or C means 2 ways

and then a digit means 10 ways 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

so in total we have 2*10*10*10 = 2000 possible codes

Hope this helps

5 0

3 years ago

Which point is in the solution set of the given system of inequalities 3x+y>-3,x+2y<4

Dima020 [189]

Step 1. Solve both inequalities for $y$ :
$3x+y\ \textgreater \ -3$
$y\ \textgreater \ -3x-3$

$x+2y\ \textless \ 4$
$2y\ \textless \ -x+4$
$y\ \textless \ - \frac{1}{2} x+2$

Step 2. To check a point in the solution of the given system of inequalities, look for the intercepts of the lines $-3x-3$ and $- \frac{1}{2} x+2$ :

$y=-3x-3$ (1)
$y=- \frac{1}{2} x+2$ (2)

Replace (1) in (2):
$-3x-3=- \frac{1}{2} x+2$
Solve for $x$ :
$\frac{5}{2} x=-5$
$x=-2$ (3)

Replace (3) in (1):
$y=-3x-3$
$y=-3(-2)-3$
$y=6-3$
$y=3$

We can conclude that the point (-2,3) is in the solution of the system if <span>inequalities</span>; also any point inside the dark shaded area of the graph of the system of inequalities is also a solution of the system.

4 0

3 years ago

Read 2 more answers

A product is made up of three parts that act independently of each other. If any of the parts is defective, the product is defec

natali 33 [55]

Answer:

The probability that a product is defective is 0.2733.

Step-by-step explanation:

A product consists of 3 parts. If any one of the part is defective the whole product is considered as defective.

The probability of the 3 parts being defective are:

P (Part 1 is defective) = 0.05

P (part 2 is defective) = 0.10 P (part 3 is defective) = 0.15

Compute the probability that a product is defective as follows:

P (Defective product) = 1 - P (non-defective product)

= 1 - P (None of the 3 parts are defective)

= 1 - P (Part 1 not defective) × P (Part 2 not defective) × P (Part 1 not defective)

$=1-[(1-0.05)\times(1-0.10)\times (1-0.15)]\\=1-[0.95\times0.90\times0.85]\\=1-0.72675\\=0.27325\\\approx0.2733$

Thus, the probability that a product is defective is 0.2733.

3 0

3 years ago

Read 2 more answers

Adding polynomials?? Your answer should be an expanded polynomial in standard form.

Gelneren [198K]

Answer:

-4b^3 + b^2

Step-by-step explanation:

5 0

3 years ago