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Brilliant_brown [7]
4 years ago
15

One kind of candy (jelly) sells for $5 a pound and another (chocolate) for $10 a pound. How many pounds of each should be used t

o make a mixture of 10 pounds of candy (both kinds) that sells for a total $80 (i.e. $8/pound)?
Mathematics
1 answer:
Vanyuwa [196]4 years ago
5 0

Answer:

  • chocolate: 6 pounds
  • jelly: 4 pounds

Step-by-step explanation:

Let x represent the number of pounds of chocolate in the mix. Then the total price of 10 pounds of mix is ...

  10x +5(10 -x) = 80

  5x +50 = 80

  5x = 30

  x = 6 . . . . . . . . pounds of chocolate

  10 -x = 4 . . . . . pounds of jelly candy

6 pounds of chocolate and 4 pounds of jelly should be used to make the mixture.

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Two angles of a triangle have the same measure and the third one is 18 degrees greater than the measure of each of the other two
kvv77 [185]

Answer:

72°

Step-by-step explanation:

Let the 2 equal angles be x then the third angle is x + 18

The sum of the 3 angles in a triangle = 180°, thus

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Solve the following triangle in which given sides are<br> a=7 b=7 c=9
blagie [28]
We have an isosceles triangle;
A=opposite angle side a.
B=opposite angle side b.
C=opposite angle side c.

A=B
Method 1:

We can divide the isosceles triangle in two right triangles,
hypotenuse=7
side=9/2=4.5

B=A=arccossine (4.5/7)=49.994799...º≈50º
C/2=90º-50º=40º  ⇒ C=2*40º=80º

Answer:
a=7;  A=50º
b=7;  B=50º
<span>c=9;  C=80º

Method 2:
Law of cosines:
a²=b²+c²-2bcCosA  ⇒CosA=(a²-b²-c²)/(-2bc)
CosA=(49-49-81) / (-126)=0.642857
A=arco cos (81/126)≈50º

B=A=50º

A+B+C=180º
50º+50º+C=180º
C=180º-100º
C=80º

Answer:

</span>a=7;  A=50º
b=7;  B=50º
<span>c=9;  C=80º</span>

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4 years ago
In a class of 34 students, 19 of them are girls.
cluponka [151]

Answer:

55.8

Step-by-step explanation:

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3 years ago
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