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Brilliant_brown [7]
3 years ago
15

One kind of candy (jelly) sells for $5 a pound and another (chocolate) for $10 a pound. How many pounds of each should be used t

o make a mixture of 10 pounds of candy (both kinds) that sells for a total $80 (i.e. $8/pound)?
Mathematics
1 answer:
Vanyuwa [196]3 years ago
5 0

Answer:

  • chocolate: 6 pounds
  • jelly: 4 pounds

Step-by-step explanation:

Let x represent the number of pounds of chocolate in the mix. Then the total price of 10 pounds of mix is ...

  10x +5(10 -x) = 80

  5x +50 = 80

  5x = 30

  x = 6 . . . . . . . . pounds of chocolate

  10 -x = 4 . . . . . pounds of jelly candy

6 pounds of chocolate and 4 pounds of jelly should be used to make the mixture.

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Answer:

1. B) 5.7

2. A) 12

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6. A) 11.2

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8. Yes, they do form a right triangle

Step-by-step explanation:

Extra tip: The hypotenuse has to be less than both sides added together, but cannot be more than either of the sides alone.

1.

16² + b² = 17²

256 + b² = 289

256 - 256 + b² = 289 - 256

b² = 33

√b² = √33

b = 5.74 or 5.7

2.

16² + b² = 20²

256 + b² = 400

256 - 256 + b² = 400 - 256

b² = 144

√b² = √144

b = 12

3.

7² + 9² = c²

49 + 81 = c²

130 = c²

√130 = √c²

11.40 or 11.4 = c

4.

7² + b² = 9²

49 + b² = 81

49 - 49 + b² = 81 - 49

b² = 32

√b² = √32

b = 5.65 or 5.7

5.

a² + 5² = 17²

a² + 25 = 289

a² + 25 - 25 = 289 - 25

a² = 264

√a² = √264

a = 16.24 or 16.2

6.

10² + b² = 15²

100 + b² = 225

100 - 100 + b² = 225 - 100

b² = 125

√b² = √125

b = 11.18 or 11.2

7.

15² + 8² = 16²

225 + 64 = 256

289 ≠ 256

8.

5² + 12² = 13²

25 + 144 = 169

169 = 169

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