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Brilliant_brown [7]
4 years ago
15

One kind of candy (jelly) sells for $5 a pound and another (chocolate) for $10 a pound. How many pounds of each should be used t

o make a mixture of 10 pounds of candy (both kinds) that sells for a total $80 (i.e. $8/pound)?
Mathematics
1 answer:
Vanyuwa [196]4 years ago
5 0

Answer:

  • chocolate: 6 pounds
  • jelly: 4 pounds

Step-by-step explanation:

Let x represent the number of pounds of chocolate in the mix. Then the total price of 10 pounds of mix is ...

  10x +5(10 -x) = 80

  5x +50 = 80

  5x = 30

  x = 6 . . . . . . . . pounds of chocolate

  10 -x = 4 . . . . . pounds of jelly candy

6 pounds of chocolate and 4 pounds of jelly should be used to make the mixture.

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What is the area of a circle with a radius of 13 millimeters? <br> (Use 3.14 for Pi.)
ludmilkaskok [199]
The area of a circle with radius of 13 millimeters is A≈530.93A=πr2=π·132≈530.92916
5 0
3 years ago
Clint and Max worked out at the gym together today. Clint works out at the gym every 4 days. Max works out at the gym every 6 da
VikaD [51]

Answer:

24 days

Step-by-step explanation:

To determine the number of days until they both work out at the gym on the same day again,

Find the lowest common multiples of 4 days and 6 days

Clint (4 days) = 8, 12, 16, 20, 24, 28, 32

Max (6 days) = 12, 18, 24, 30, 36, 42

The lowest common multiple of ,4 days and 6 days is 24 days

Therefore, the number of days until they both work out at the gym on the same day again is 24 days

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D" id="TexFormula1" title="\frac{3}{4}" alt="\frac{3}{4}" align="absmiddle
oee [108]

\frac{3}{4}  +  \frac{5}{16}  \\  \\  \frac{12}{16}  +  \frac{5}{16} \\  \\  \frac{17}{16}
5 0
3 years ago
What could this be???????
Step2247 [10]
Your answer is A it's a pretty simple task that you may just be overthinking
8 0
3 years ago
Read 2 more answers
Please help me, will mark you as brainiest! Don’t answer if you don’t know it!
Vesnalui [34]

Answer:

The correct option is;

26.8

Step-by-step explanation:

The given parameters are;

The perpendicular bisectors of the sides of ΔMNP = Segments OQ, OR, and OS

Therefore;

in Segment MN, segment QM = segment QN, by definition of bisected line

Segment OQ = Segment OQ by reflexive property

∠OQM = ∠OQN = 90° by definition of perpendicular bisector

∴ ΔOQN ≅ ΔOQM, by SAS rule of congruency

Segment MO ≅ Segment ON by Congruent Parts of Congruent Triangle are Congruent, CPCTC

Segment MO = Segment ON = 26.8, by definition of congruency

Segment MO = 26.8

6 0
3 years ago
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