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2 years ago

The coordinate plane below represents a city. Points A through F are schools in the city.

Mathematics

1 answer:

Nutka1998 [239]2 years ago

4 0

PART A: The equation I used is y≥-1x+4. The line will be graphed going diagonally from the second quadrant to the fourth quadrant and shaded above the line.

PART B: Plug in the coordinates for point C and F into the equation from PART A and solve them to make sure the statements are true. You should end up with 2≥2 for point C and 4≥1 for point F.

PART C: First graph the equation and then shade below the line. Next, identify all the points in the shaded area.

I hope this helps you! I have provided pictures of both equations for reference. The first picture is for PART A and PART B. The second picture is for PART C. Let me know if I'm correct :)

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Can someone help me 10 points

Elanso [62]

The two angles form a right triangle which is 90 degrees.

Add the two to equal 90:

3x-8 + 4x = 90

simplify:

7x-8 = 90

Add 8 to both sides:

7x = 98

Divide both sides by 7:

x = 14

3 0

2 years ago

Which of the following represents fifth root of x to the fourth power in exponential form? (6 points) a 4x5 b 5x4 c x to the fiv

sleet_krkn [62]

Answer:

B) 5x4

one its not A nor its C

its either B or D but i would go with B because D doesn't make sense all because D is saying x4^5 but its 5x^4

3 0

2 years ago

Read 2 more answers

The given line passes through the points (-2,-4) and (2,2) What is the equation, in point-slope form, of the line that is parall

Morgarella [4.7K]

Answer:

$(y-1)=\frac{3}{2}(x+3)$

Step-by-step explanation:

The point slope form of a line is $(y-y_1)=m(x-x_1)$ where $x_1=-3\\y_1=1$ . We write

$(y-1)=m(x--3)\\(y-1)=m(x+3)$

Since the line is parallel to the line shown it will have the same slope. To find m, count the slope from each marked point on the graph. Count the rise then the run and create a fraction rise/run. The slope is 6/4 which simplifies to 3/2. Now substitute it for m.

$(y-1)=\frac{3}{2}(x+3)$

3 0

3 years ago

Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif

dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

Step:-1

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals $t_{0.01} =2.82$ (from tabulated value).

$The mean value = 0.0365$

$x±t_{0.01} \frac{S}{\sqrt{n-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{22} }$

$0.0365±2.82 \frac{0.0046}{4.690 }$

using calculator

$0.0365±0.00276$

Confidence interval is

$(0.0365-0.00276,0.0365+0.00276)$

$(0.0338,0.0392)$

the mean value is lies between in this confidence interval

(0.0338,0.0392).

Answer:-

using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.

4 0

2 years ago

Value of m varies directly as value of n and n=5 when m=12. What is n when m=18?

ohaa [14]

Simplify the problem down, so:

m = 12 & n = 5
m = 6 & n = 2.5 (divided each number by 20)

Now m is a factor of 18. Multiply each number by 3.
Answer: m = 18 & n = 7.5

6 0

3 years ago