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statuscvo [17]
2 years ago
12

Find the angle in the attachment​

Mathematics
1 answer:
Vadim26 [7]2 years ago
7 0
Right-angled triangle. Let x be the required angle. Tan x = 8/6. x= 53.1°
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Right in equation of the ellipse The rest of the question is in the photo
Tju [1.3M]

Answer:

1) The vertices are (-5 , 0) and (5 , 0)

  The co-vertices are (0 , -2) and (0 , 2)

  The foci are (-√21 , 0) and (√21 , 0)

2) The equation of the ellipse ⇒ x²/48 + y²/64 = 1

Step-by-step explanation:

1) ∵ 4x² + 25y² = 100 ⇒ ÷ 100

∴ x²/25 + y²/4 = 1

∵ The standard equation of the ellipse with center (0 , 0) is

   x²/a² + y²/b² = 1

∴ a² = 25 ⇒ ∴ a = ±5

∴ The vertices are (-5 , 0) and (5 , 0)

∴ b² = 4 ⇒ ∴ b = ±2

∴ The co-vertices are (0 , -2) and (0 , 2)

∵ c² = a² - b²

∴ c² = 25 - 4 = 21

∴ c = ±√21

∴ The foci are (-√21 , 0) and (√21 , 0)

2) ∵ Its center is (0 , 0)

∵ The vertex of it is (0 , -8)

∴ a² = 64

∵ The focus is (0 , 4)

∴ c² = 16

∵ c² = a² - b²

∴ b² = a² - c² = 64 - 16 = 48

∵ b² = 48

The standard equation of the ellipse with center (0 , 0) is

   x²/b² + y²/a² = 1 ⇒ major axis // to y-axis

∴ x²/48 + y²/64 = 1

6 0
3 years ago
Is the function shown in the graph one-to-one?
brilliants [131]

Answer:

What graph?

Step-by-step explanation:

6 0
3 years ago
Plz help and plz don’t just answer for points.<br> What is the answer for a b and c?
Liono4ka [1.6K]

Answer:

b the answer for your exit ticket

7 0
3 years ago
Read 2 more answers
Write the equation of the line perpendicular to y=2/3 x−12 that passes through the point (4, -1) in slope-intercept form.
xenn [34]

Answer:

Step-by-step explanation:

perp. -3/2

y + 1 = -3/2(x - 4)

y + 1 = -3/2x + 6

y = -3/2x + 5

7 0
3 years ago
Find an equation (in term of x) of line through the points (-1,3) and (1,4)
Serjik [45]
ANSWER

The equation is
2y - x = 7


EXPLANATION

The equation of the line that passes through the point (-1,3) and (1,4) can be found using the formula,

y-y_1=m(x-x_1)

where

m =  \frac{4 - 3}{1  -  - 1}

m =  \frac{1}{2}
is the slope and

(x_1,y_1)
is a point on the line.



The equation of the line becomes,


y - 4 =  \frac{1}{2} (x - 1)


Multiply through by 2 to get,.

2y - 8 = x - 1

Or

2y - x = 7
4 0
3 years ago
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