Answer:
A3-a-c=b assuming you mean A=![\frac{a+b+c}{3}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%2Bb%2Bc%7D%7B3%7D)
Step-by-step explanation:
Basically, we'll be using properties of equalities to "balence out the equation" and shift all variables except for b to one side
1) Use multiplication prop. of equality
This property states that if we multiply one side we must multiply the other. We'll be doing this for the "3" portion.
3(A)=3((a+b+c)/3)
3A= a+b+c
2) Use subtraction prop of equality
This one states that if we subtract one side we must subtract the other. We will be doing this for the "a" and "c" portion
(3A)-a=(a+b+c)-a
3A-a=b+c
(3A-a)-c=(b+c)-c
3A-a-c=b
Hopefully that helps a bit T_T
Answer:
28
Step-by-step explanation:
This problem is certainly an interesting one. I would say that they wrote 28 word problems becuase it didn't say anything about writing more of them, and the problem also specifically stated that "we" stopped writing word problems due to him being upset.
I feel like I might be wrong; however this problem involves a bunch of misleading, unnessecary information, so it might as well be a trick problem.
10 total pieces of the pie
-5
-2
And only 3 remained so your answer would be
3/10
Answer:-4
-3
-2
Step-by-step explanation:
thx
Answer:
C) 2,6,24,120,720
Step-by-step explanation:
Here the n-th term An = ![\frac{(n +2)!}{n + 2}](https://tex.z-dn.net/?f=%5Cfrac%7B%28n%20%2B2%29%21%7D%7Bn%20%2B%202%7D)
A1 is the first term
A1 = (1 + 2)!/(1 + 2)
= 3!/3
A1 = 2
A2 is the second term
A2 = (2 +2)!/(2 +2)
= 4!/4
A2 = (1*2*3*4) /4
A2 = 6
A3 is the third term
A3 = (3 + 2)!/(3 +2)
A3 = 5!/5
A3 = 24
A4 is the fourth term
A4 = (4 + 2)!/(4 + 2)
A4 = 6!/6
A4 = 120
A5 is the fifth term
A5 = (5 + 2)!/(5 +2)
A5 = 7!/7
A5 = 720
Answer: C) 2,6,24,120,720
Thank you.