Answer:
Mass of water == 1.71 g
Explanation:
Given data:
Initial temperature of water = 10°C
Final temperature of water = 50°C
Energy absorbed = 286 J
Mass of water = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 50°C - 10°C
ΔT = 40°C
by putting values,
286 J = m × 4.18 J/g.°C × 40°C
286 J = m × 167.2 J/g
m = 286 J / 167.2 J/g
m = 1.71 g
Isotopic notation of phosphorus-29 is 
Explanation:
- Isotopes are atoms with equal number of protons but different number of neutrons at its nucleus.
- The isotopic notation for any element can be written as
where X represents the chemical symbol ,A represents mass number and Z represents atomic number - The atomic number for phosphorus is 15
- Isotope's mass number for phosphorus-29 is 29
- The chemical symbol for phosphorus is P
- Hence Isotopic notation is

- Number of neutrons = 29-15 =14
- Number of protons=atomic number =15
Answer:
A
Explanation:
Protons and neutrons make up nearly all the mass of an atom, and each is worth 1 amu. Each atom of an element has a mass measured in amu; thus, its weighted average, or atomic mass, is measured in amu.
Electrons are way way way....lighter so protons and neutrons are taken into account when doing atomic mass.
Kinetic energy is the energy an object has because of its motion.
Answer:
1.82x10⁻¹⁹Joules is the energy of the photon that is absorbed by the electron.
Explanation:
The energy of a photon is given by the equation:
E = h×ν
<em>Where E is energy of the photon in Joules.</em>
<em>h is Planck's constant (6.6262x10⁻³⁴Js)</em>
<em>And ν is frequency of the photon (In Hz = s⁻¹)</em>
<em />
The frequency of the photon is 2.74x10¹⁴Hz. That means its energy is:
E = 6.6262x10⁻³⁴Js × 2.74x10¹⁴s⁻¹
E =
<h3>1.82x10⁻¹⁹Joules is the energy of the photon that is absorbed by the electron</h3>
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