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IrinaK [193]
3 years ago
15

What is the absolute value of 6.75?

Mathematics
2 answers:
dusya [7]3 years ago
6 0
6.75 is the absolute value of 6.75 absolute value is distance from zero and 6.75 is 6.75 from 0 so is -6.75
iren [92.7K]3 years ago
5 0
I think it is |6.75|, hope I helped you. The reason I say is because absolute value is the POSITIVE value of any number. :)
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4 years ago
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A submarine lies 3 kilometers from the path of a target ship. The sub’s torpedoes have a range of 5 kilometers. For what distanc
aev [14]

The distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

Explanation:

The submarine lies 3 km from the target ship.

Let B denotes the target ship and C denotes the submarine.

Let AC denotes the the target ship would be within the range of the torpedoes.

The image attached below illustrates that the distance between submarine and the target ship and the range of the torpedoes.

Let BC denotes the distance between the target ship and the submarine. Let AC denotes the range of the torpedoes.

To determine the length of AB, let us use Pythagorean theorem,

AC^{2} =AB^{2} +BC^{2}

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5^{2} =AB^{2} +3^{2}

Squaring the terms, we get,

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5 0
4 years ago
The drawing plan for an art studio shows a rectangle that is 17.2 inches by 6 inches. The scale in the plan is 2 in.: 5 ft. Find
Norma-Jean [14]

Answer:

The length is 43 feet, the width is 15 feet, and the area is 645 square feet

Step-by-step explanation:

Let us solve the question

∵ The drawing plan shows a rectangle that is 17.2 inches by 6 inches

∴ The drawing length = 17.2 inches

∴ The drawing width = 6 inches

∵ The scale in the plan is 2 in.: 5 ft

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→  inches: feet

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→  17.2     : L

→  6         : W

→ By using the cross multiplication

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→ Divide both sides by 2

∴ W = 15 feet

∴ The actual width is 15 feet

∵ The area of the rectangle is A = L × W

∵ L = 43 feet

∵ W = 15 feet

→ Substitute them in the rule of the area

∴ A = 43 × 15

∴ A = 645 feet²

∴ The actual area is 645 square feet

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