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3 years ago

Round to the nearest hundredth: 0.13658537

Mathematics

2 answers:

tino4ka555 [31]3 years ago

5 0

Answer:

.14

Step-by-step explanation:

Montano1993 [528]3 years ago

3 0

Answer is 0.14

in nearest

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13. A smoothie shop has 40 stores, and 55% of the stores are in

S_A_V [24]

Answer:

You could answer this two ways.

Step-by-step explanation:

Method 1: Set up proportion

x/40=55/100

Cross-multiply and you will get..

2200=100x

x=22

Method 2: Use decimals

As we saw in the first method, 55 percent is equal to 55/100. 55/100 is equal to 0.55.

You can multiply 0.55 and 40 to get the answer as well.

0.55 times 40 is 22.

Hope this explanation helped! ☺️

6 0

3 years ago

Read 2 more answers

Please help. I’ll mark you as brainliest if correct!

In-s [12.5K]

Answer:

Step-by-step explanation:

f^-1(x) =dy/dx

dy/dx(8x+9)=8

8 0

3 years ago

The gross weekly sales at a certain restaurant are a normal random variable with mean $2200 and standard deviation $230.What is

Lesechka [4]

Answer:

a) The total gross sales over the next 2 weeks exceeds $5000 is 0.0321.

b) The weekly sales exceed $2000 in at least 2 of the next 3 weeks is 0.9033.

Step-by-step explanation:

Given : The gross weekly sales at a certain restaurant are a normal random variable with mean $2200 and standard deviation $230.

To find : What is the probability that

(a) the total gross sales over the next 2 weeks exceeds $5000;

(b) weekly sales exceed $2000 in at least 2 of the next 3 weeks? What independence assumptions have you made?

Solution :

Let $X_1$ and $X_2$ denote the sales during week 1 and 2 respectively.

a) Let $X=X_1+X_2$

Assuming that $X_1$ and $X_2$ follows same distribution with same mean and deviation.

$E(X)=E(X_1+X_2)=E(X_1)+E(X_2)$

$E(X)=2\mu = 2(220)=4400$

$\sigma_X=\sqrt{var(X_1+X_2)}$

$\sigma_X=\sqrt{2\sigma^2}$

$\sigma_X=\sqrt{2}\sigma$

$\sigma_X=230\sqrt{2}$

So, $X\sim N(4400,230\sqrt{2})$

$P(X>5000)=1-P(X\leq5000)$

$P(X>5000)=1-P(Z\leq\frac{5000-4400}{230\sqrt{2}})$

$P(X>5000)=1-P(Z\leq1.844)$

$P(X>5000)=1-0.967$

$P(X>5000)=0.0321$

The total gross sales over the next 2 weeks exceeds $5000 is 0.0321.

b) The probability that sales exceed teh 2000 and amount in at least 2 and 3 next week.

We use binomial distribution with n=3.

$P(X>2000)=1-P(X\leq2000)$

$P(X>2000)=1-P(Z\leq\frac{2000-2200}{230})$

$P(X>2000)=1-P(Z\leq-0.87)$

$P(X>2000)=1-0.1922$

$P(X>2000)=0.808$

Let Y be the number of weeks in which sales exceed 2000.

Now, $P(Y\geq 2)$

So, $P(Y\geq 2)=P(Y=2)+P(Y=3)$

$P(Y\geq 2)=^3C_2(0.8077)^2\cdot (1-0.8077)+^3C_3(0.8077)^3$

$P(Y\geq 2)=0.37635+0.52692$

$P(Y\geq 2)=0.90327$

The weekly sales exceed $2000 in at least 2 of the next 3 weeks is 0.9033.

3 0

3 years ago

Find the mean of the data in the dot plot below.

ladessa [460]

Answer:

The answer would be, 2.75

Step-by-step explanation:

Add all the numbers up:

0+1+1+2+3+4+5+6=22

Divide the answer by the amount of numbers:

22÷8=2.75

4 0

3 years ago

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Calculate the perimeter of this figure<br> to the nearest tenth.<br> P = [? ] ft

sergejj [24]

40.9 ft
You would add each side together 10 plus 10 is 20 then 20 plus 8.9 is 28.9 then 28.9 plus 8 is 36.9 plus four which is 40.9

4 0

3 years ago