A train car is 50.6ft this is 5.8 feet less than 6 times the width what is the width

2 answers:

7 0

Data: Adopting: w (width)

50.6 = 6*w - 5.8

Solving:

$50.6 =6*w - 5.8$
$50.6 + 5.8 = 6w$
$56.4 = 6w$
$6w = 56.4$
$w = \frac{56.4}{6}$
$\boxed{\boxed{w = 9.4\:ft}}\end{array}}\qquad\quad\checkmark$

Answer:
$\textbf{\underline{The\:width\:is\:9.4\:feet}}$

Strike441 [17]3 years ago

4 0

9.4 inches. (50.6 + 5.8) / 6 = 9.4 fairly simple

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Explain how to estimate the quotient using compatible numbers.plz help fast

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3 0

3 years ago

Use the definition mtan=lim

Leokris [45]

(a) mtan refers to the slope of the tangent line. Given f(x) = 9 + 7x ², compute the difference quotient:

$\dfrac{f(x+h)-f(x)}h = \dfrac{(9+7(x+h)^2)-(9+7x^2)}h = \dfrac{(9+7x^2+14xh+7h^2)-9-7x^2}h = \dfrac{14xh+7h^2}h$

Then as h approaches 0 - bearing in mind that we're specifically considering h near 0, and not h = 0 - we can eliminate the factor of h in the numerator and denominator, so that

$m_{\rm tan} = \displaystyle \lim_{h\to0}\frac{f(x+h)-f(x)}h = \lim_{h\to0}\frac{14xh+7h^2}h = \lim_{h\to0}(14x+7h) = 14x$