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rusak2 [61]
2 years ago
6

A system of equations has no solution. If y = 8x + 7 is one of the equations, which could be the other equation? 2y = 16x +14 y

= 8x – 7 y = –8x + 7 2y = −16x − 14
Mathematics
2 answers:
Assoli18 [71]2 years ago
6 0

Answer:

B

Step-by-step explanation:

I got 100% on edge 2020 quiz

Juliette [100K]2 years ago
5 0

Answer:

I think its y=8x-7

Step-by-step explanation:

Pls tell me if i'm wrong.

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What is the greatest remainder you could have with the divisor 3? With the divisor 8? With the divisor 5?
Morgarella [4.7K]
2,7,4...... I think these are the answer
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3 years ago
Can someone explain these questions to me, especially the last one please.​
Firlakuza [10]

Answer:

Step-by-step explanation:

A is 0.5 x 10 because the thickness of the sheets is 0.5 and there are ten sheets stacked together that thickness so how thick is the pile.

for B it is the answer of A plus one more sheet which is ( answer for A) + 0.5

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4 0
3 years ago
Heres yo go mattty lolololololol
gladu [14]

Answer:

x = 16

Step-by-step explanation:

71 - 15 = 56

56 ÷ 14 = 4

\sqrt{16} = 4

<u>Check work:</u>

\sqrt{16} = 4

14 x 4 = 56

56 + 15 = 71

7 0
3 years ago
X+71=7x+5 <br><br> Help help help
IrinaVladis [17]
The answer to your question would be -6x+76
7 0
3 years ago
Read 2 more answers
In how many arrangements can 3 boys and 4 girls stand in a row such that no two boys are together?
Sophie [7]

Answer: 1440

Step-by-step explanation:

To arrange 3 boys and 4 girls such that no two boys are together.

Since boys should be arranged between the girls.

So first arrange the girls.

Assume that the girls are placed, then there will be 5 spaces left for 3 boys.

The number of combinations to fill these places = ^5C_3=\dfrac{5!}{3!2!}=\dfrac{5\times4}{2}=10

Also, 3 boys can arrange themselves in 3! =3 x 2 x 1 = 6 ways

4 girls can arrange themselves in 4! = 4x 3 x 2 x 1 = 24 ways

Then, the total number of arrangements = 10 x 6 x 24 = 1440

Hence, the required number of arrangements = 1440

5 0
3 years ago
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