This can be solve by using the average cans of each student
collected and muliply it by the total students. Since for ms. Lee has 24
students and each student collected 18 cans on average, so the total can her
class collected on average is 432 cans. For mr galveshas 21 students and
collected 25 can per syudents on average, so the total is 525 cans. So 525 –
432 = 93 more cans the class of mr galvez collected
Answer:
a. 11.26 % b. 6.76 %. It appears so since 6.76 % ≠ 15 %
Step-by-step explanation:
a. This is a binomial probability.
Let q = probability of giving out wrong number = 15 % = 0.15
p = probability of not giving out wrong number = 1 - q = 1 - 0.15 = 0.75
For a binomial probability, P(x) = ⁿCₓqˣpⁿ⁻ˣ. With n = 10 and x = 1, the probability of getting a number wrong P(x = 1) = ¹⁰C₁q¹p¹⁰⁻¹
= 10(0.15)(0.75)⁹
= 1.5(0.0751)
= 0.1126
= 11.26 %
b. At most one wrong is P(x ≤ 1) = P(0) + P(1)
= ¹⁰C₀q⁰p¹⁰⁻⁰ + ¹⁰C₁q¹p¹⁰⁻¹
= 1 × 1 × (0.75)¹⁰ + 10(0.15)(0.75)⁹
= 0.0563 + 0.01126
= 0.06756
= 6.756 %
≅ 6.76 %
Since the probability of at most one wrong number i got P(x ≤ 1) = 6.76 % ≠ 15 % the original probability of at most one are not equal, it thus appears that the original probability of 15 % is wrong.
Answer:
y = |x| + 7
Step-by-step explanation:
Use desmos.com to see it in action
Answer:
Step-by-step explanation:
1. -35, 2
2. -72, -6
3. -16, 0
4. 40, 13
5. -15, 2
6. -30, 7
7. 30, 11
8. 42, -13
9. -3, -24
10. -4, 20
11. 7, 1
12. 4, -24
13. -7, -70
14. 4, 9
15. 7, -3
16. 9, 3
17. -10, 11
18. 6, -5
19. 11, 6
20. 1, -9
21. -9, 4
22. -8, 7
23. 6, 4
24. -7, -5
25. 11, 4
26. 10, 3
27. -8, 5
28. -9, 0
Sallys statement is always true
for example:
-6 + 2 = -4
but if I turn it around
2 - 6 = -4
same answer
-6 -6 = -12
swap around -6 - 6 = 12
same answer
again -3 + 6 = 3
and 6 - 3 = 3
