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Sliva [168]
3 years ago
12

Please help someone

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0

Answer:

=45 b/c all we have to do is subtract the higher number to the lowest number.

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0 = 2x2 - 6x + 4<br> What are the solutions to
Ainat [17]
The answer would be .5
6 0
3 years ago
Read 2 more answers
Leah's house has media room with a large flat screen tv. The media room tv has a width of 8 feet and a height of 4.5 feet. The f
neonofarm [45]
The ratio of the media room tv's width to height is 8ft to 4.5ft or 8/4.5

since the ratio of the living room tv's width to height is the same, the ratio would be
x/27 = 8/4.5
with x being the living room tv's width. Solve for x
x = (8/4.5)(27)
   = 48
The width of the living room tv is 48 inches
4 0
3 years ago
Read 2 more answers
A bag has 9 marbles: 4 are green, 2 are red, and 3 are blue. Melissa chooses a marble at random, and without putting it back, ch
nika2105 [10]

Answer: pr (blue) = 1/3 or 0.33

Pr(green without replacement) = 1/2 = 0.5

Step-by-step explanation:

Probability = number of possible outcomes/ number of total outcomes

Total number of outcomes is the sum of all the marbles, given as 9

Pr ( first marble blue) = no of blue marbles/ total number of marbles

= 3/9 = 1/3 or 0.333

Second marble is chosen without replacement- this means that the total outcome has reduced by 1, total number of marbles has reduced to 8 because there was no replacement.

Pr (second marble is green) = number of green marble/ total number of marbles without replacing the first marble

= 4/8 = 1/2 = 0.5

I hope this helps.

7 0
3 years ago
NEED HELP BEING TIMED
Virty [35]

Answer:

The answer is A.

The value of the 1 in the one's place is 10 times​ the value of the 1 in the tenths place.

Step-by-step explanation:

7 0
3 years ago
Jason is mikes older brother. the sum of their ages is 25. the differnece in their ages is 7 write the system of equation that r
Jet001 [13]

Answer:

Equation 1: m+j=25

Equation 2: j=m+5


I hope this helps! Good luck! <3


-YAND3R3


5 0
3 years ago
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