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2 years ago

Kate's 85 on her english test was 37 points less than twice the grade on her science test.

Mathematics

1 answer:

Sever21 [200]2 years ago

5 0

58+37 is 122 since its double / by 2 and you get 61

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X (dy/dx) = (y-1/y+1)-y

notsponge [240]

F' $( \frac{y-1}{y+1})-y$ =
f' $( \frac{y-1}{y+1})$ -f'(y) [/tex]=
$\frac{f'(y-1)(y+1)-f'(y+1)(y-1)}{(y+1)^2} -1$ =
$\frac{(f'(y)-f'(1))(y+1)-(f'(y)+f'(1))(y-1)}{(y+1)^2} -1$ =
$\frac{(1-0)(y+1)-(1-0)(y-1)}{(y+1)^2} -1$ =
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8 0

2 years ago

1)Shannon takes a class to learn Japanese.The class costs $243 and lasts for 12 weeks.what is the cost,per week,of the Japanese

miskamm [114]

243 divided by 12 is $20.25

5 0

2 years ago

Read 2 more answers

The table shows the height of several buildings in Chicago. Use the table to determine whether the height of the building is a l

guajiro [1.7K]

Answer:

no (mark brainlest plz)

Step-by-step explanation:

because North tower dips down when its the highest. Its also not linear because it +5 then +30 all the sudden

8 0

2 years ago

The National Center for Educational Statistics surveyed 5400 college graduates about the lengths of time required to earn their

fenix001 [56]

Answer:

The 90% confidence interval for the mean time required by all college graduates is between 5.36 years and 5.44 years.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645*\frac{1.9}{\sqrt{4500}} = 0.04$

The lower end of the interval is the sample mean subtracted by M. So it is 5.4 - 0.04 = 5.36 years.

The upper end of the interval is the sample mean added to M. So it is 5.4 + 0.04 = 5.44 years.

The 90% confidence interval for the mean time required by all college graduates is between 5.36 years and 5.44 years.

3 0

2 years ago

15 point question. please help

uysha [10]

(2,3) , (0,-3) , (-2,1) are the points.
Hope this helps... Let me know if you wanna know anything.

5 0

2 years ago