Distance=speed times time
distance/time=speed
distance=538
time=9 and 15mins
60mins=1hr
15/60=1/4=0.25
time=9.25hr
distance/time=538/9.25=58.162mph
about 58mph
The box plot that would confirm the inference that Linda made would have a minimum value of 20 and a maximum value of 40. Somewhere in the between is the mean. The box plot should have a confidence interval of 95% in order to have the inference valid.<span />
Answer:
The answer is 36
Step-by-step explanation:
Let the number be <em>x</em>
x/40 is her mark
she got 90% mark correct
x/40 x 100 = 90
by cancellation we get 9 x 4 = 36
HOPE THIS HELPS
Y-5=3-9 (y+2)
Solve for y
Distribute the 9 to (y+2)
Y-5=3-9y-18
Y-5=-15-9y
+9y to both sides
10y-5=-15
+5 to both sides
10y=-10
÷10 both sides
Y= -1
2 (x-7)-10=12-4x
Solve for X
Distribute 2 to (x-7)
2x-14-10=12-4x
2x-24=12-4x
+4x to both sides
6x-24=12
+24 to both sides
6x=36
÷6 to both sides
X=6
X = # of posters, y = total cost
y = 2x + 250
y = 1000
1000 = 2x + 250
1000 - 250 = 2x
750 = 2x
750/2 = x
375 = x....so 375 posters can be printed
==========================
y = total cost, x = # of miles
y = 3x + 3
y = 117
117 = 3x + 3
117 - 3 = 3x
114 = 3x
114/3 = x
38 = x.....so the car was towed 38 miles
