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nasty-shy [4]
3 years ago
12

Please dont steal points only real answers

Mathematics
1 answer:
morpeh [17]3 years ago
8 0
1. 4 1/5
2. 11/24
3. 12 1/4
4. 2
5. 3 5/12

I did the math but I’m sorry if it’s not all correct
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Jack leaves school to go home, He walks 6 blocks North and then 8
inysia [295]
Jack is 10 blocks away from the school
3 0
3 years ago
The compound interest on Rs. 50000 at 4% per annum for 2 years compound annually is
statuscvo [17]

Answer:

$54080

Step-by-step explanation:

Step one:

given

principal= Rs. 50000

rate= 4%= 0.04

time= 2 years

Required

The final Amount A

Step two

Applying

A= P(1+r)^t

substitute

A= 50000(1+0.04)^t

A= 50000(1.04)^2

A= 50000*1.0816

A= 54080

$54080

6 0
3 years ago
Which transformation will carry pentagon EFGHI onto itself?
wariber [46]

Answer:

D

Step-by-step explanation:

The pentagon has 5 interior angles that add up to 360. To find the angle of rotational symmetry, divide 360 by 5 (you get 72). So if you rotated the shape 72 degrees, it will map onto itself. 72 times 2 is 144, and that's rotating the shape 72 degrees twice, so it will stay the same.

7 0
3 years ago
(3Q) Find the amplitude and period of f(t)= -tan.0t
Vanyuwa [196]

Answer:

It has no amplitud and the period is 5pi/2

Step-by-step explanation:

Given a function of the following type:

f(t) = AtanB(t + C)

The function has no amplitud, given that it doesn't have maximum or minimum value.  And the period is given by: pi/B

In this case, we have f(t)= -tan0.4t. Then:

B = 0.4

⇒ Period = pi/0.4 = 5pi/2

Therefore, the answer is: It has no amplitud and the period is 5pi/2

8 0
3 years ago
given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta
lapo4ka [179]

Answer:

\cos{\theta} = \frac{\sqrt{15}}{4}

Step-by-step explanation:

For any angle \theta, we have that:

(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1

Quadrant:

0 \leq \theta \leq \frac{\pi}{2} means that \theta is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1

(\frac{1}{4})^{2} + (\cos{\theta})^{2} = 1

\frac{1}{16} + (\cos{\theta})^{2} = 1

(\cos{\theta})^{2} = 1 - \frac{1}{16}

(\cos{\theta})^{2} = \frac{16-1}{16}

(\cos{\theta})^{2} = \frac{15}{16}

\cos{\theta} = \pm \sqrt{\frac{15}{16}}

Since the angle is in the first quadrant, the cosine is positive.

\cos{\theta} = \frac{\sqrt{15}}{4}

3 0
3 years ago
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