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sleet_krkn [62]

3 years ago

11

Dan enrolls in a basketball league for people over 40. He pays the following fees. --$25 for a team t-shirt --his share of the t

eam’s $110 enrollment fee.

1 answer:

I am Lyosha [343]3 years ago

5 0

I think that you should provide more details

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A.S.A.P PLEASE HELP

Monica [59]

To solve this problem yu must apply the proccedure shown below:

1. You have that the <span>focus of the parabola is located at (0,–2) and the directrix is represented by y=2. Therefore, you have:
</span>
√(x0-0)²+(y0-(-2))²=|y-2|

2. By simplifying and clearing x², you obtain:

(√x0²+(y0+2)²)²=(y0-2)²
x0²+(y0+2)²=(y0-2)²

{ Note: x0²=x and y0=y)

x²=-8y

The answer is: x²=-8y

4 0

3 years ago

What is the theoretical probability that the spinner lands on red?

Archy [21]

Green 6 Can you answer this question for me please 1. What can you see in the picture? 2. What do you think the artist is trying to tell us in the painting? 3. Describe the character of the artist in three words.

6 0

3 years ago

Read 2 more answers

2root3 sin^<a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="ac9eec">[email protected]</a> - <a href

Phantasy [73]

Answer:

Step-by-step explanation:

$2\sqrt{3} sin^{2} \alpha -cos\alpha =0\\2\sqrt{3} (1-cos ^2 \alpha )-cos \alpha =0\\2\sqrt{3} -2\sqrt{3} cos^2 \alpha -cos \alpha =0\\2\sqrt{3} cos^2 \alpha +cos \alpha -2\sqrt{3} =0\\cos \alpha =\frac{-1 \pm\sqrt{1^2-4*2\sqrt{3}*(-2\sqrt{3}) } }{2*2\sqrt{3} } \\=\frac{-1 \pm\sqrt{1+48} }{4\sqrt{3} } \\=\frac{-1\pm7}{4\sqrt{3} } \\either~cos \alpha =\frac{6}{4\sqrt{3} }=\frac{\sqrt{3} }{2} \\=cos \frac{\pi }{6} ,cos(2\pi -\frac{\pi }{6} )\\=cos \frac{\pi}{6} ,cos \frac{11\pi }{6}$

$\alpha =2 n\pi+ \frac{\pi }{6} ,2n\pi +\frac{11\pi }{6} (general~solution)$

$or~cos\alpha =-\frac{7}{4\sqrt{3} } \\ \alpha =cos^{-1}( \frac{-7}{4\sqrt{3} } )$

5 0

3 years ago

Which congruency statements could be correct for the figures? Check all that apply. MNOP ≅ STUV MNPO ≅ TSVU NPOM ≅ VUTS OPNM ≅ T

jeka94

Answer:

NPOM ≅ VUTS

OPNM ≅ TUVS

Step-by-step explanation: Given: two quadrilaterals having verticals P, N, O,M and S,T,V,U are congruent, where, OM is congruent or equal to TS and in quadrilaterals NPOM and VUTS-

since, the condition and, side UV=side OM follow for the above quadrilateral. (According to the figure)

then we can say according to the property of quadrilateral, their corresponding sides must be congruent. so they are congruent.

7 0

2 years ago

Read 2 more answers

Someone please help me I really need help !!!!

DanielleElmas [232]

Answer:

$\frac{71}{100}$

<h3>Answer c</h3>

Step-by-step explanation:

$\frac{14}{100} = squash \\ \frac{3}{20} = \frac{15}{100} = tennis \\ \frac{14 +1 5}{100} = \frac{29}{100} \\ \\ \frac{100}{100} - \frac{29}{100 } \\ = \frac{71}{100} = rugby$

5 0

2 years ago