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Levart [38]
3 years ago
14

A radio station plays commercials for 5 1/6 minutes each hour. How many 31-second commercials can it play?

Mathematics
1 answer:
Anna007 [38]3 years ago
7 0

Answer:

6 commercials.

Step-by-step explanation:

To figure this out, you would have to divide 5 1/6 and 31.

31 ÷ 5 1/6 = 6

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In 1960, the population of a town was 14 thousand people. Over the course of the next 50 years, the town grew at a rate of 30 pe
andre [41]

SOLUTIONS

Given: Assume y is the population

\begin{gathered} t=0=1960,y=14030 \\ t=1=1961,y=14060 \\ so\text{ b = 14000} \\ so\text{ k = 30} \end{gathered}

The town grow at the rate of 30 people per year.

y=kt+14000y=30t+14000

(A) The population predicted to be in 2030 will be

\begin{gathered} 2030-1960=70 \\ y=30k+14000 \\ y=30(70)+14000 \\ y=2100+14000 \\ y=16100people \end{gathered}

(B) so when y = 15000, find t

\begin{gathered} y=15000 \\ y=30t+14000 \\ 15000=30t+14000 \\ 15000-14000=30t \\ 1000=30t \\ t=\frac{1000}{30} \\ t\approx33 \\ t=1960+33 \\ t=1993 \end{gathered}

3 0
1 year ago
In the diagram below AB is parallel to CD what is the value of y
Mashutka [201]

Answer:

y=60 due to adjacent angle

5 0
3 years ago
Read 2 more answers
Abraham told his friends to try and guess his number. He said that when you take his number and multiply it by 4 and add 12 you
lisov135 [29]

Answer:

C) 22

Step-by-step explanation:

I have set up an equation based off of what Abraham said.

(n*4)+12=100\\\\4n+12=100\\\\4n+12-12=100-12\\\\4n=88\\\\\frac{4n=88}{4}\\\\\boxed{n=22}

The number should be 22.

Hope this helps.

Hope this helps.

8 0
3 years ago
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Betsy caught three fish. The weights of the fish were 3 lb 2 oz, 2 lb 11 oz, and 2 lb 8 oz. What was the total weight of the thr
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Answer:

8 lbs 5 oz

Step-by-step explanation:

When you add 3 lbs, 2 lbs, and 2 lbs you get 7 lbs.

There are 16 oz in a lb. When you add the number of oz you get 21 oz which is the same as 1 lb and 5 oz.

you then add 7 lbs to 1 lb and 5 oz and get 8 lbs and 5 oz.

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Please HELPP!!! Solve the system of equations.<br> y= 2x<br> y= x^2 - 15
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y=2x\\y=x^2-15\\\\x^2-15=2x\\x^2-2x-15=0\\x^2-5x+3x-15=0\\x(x-5)+3(x-5)=0\\(x+3)(x-5)=0\\x=-3 \vee x=5\\\\y=2\cdot(-3) \vee y=2\cdot5\\y=-6 \vee y=10\\\\(x,y)\in\{(-3,-6),(5,10)\}

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