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coldgirl [10]
3 years ago
13

D = 7.9 cm Calculate the circumference of the circle.

Mathematics
1 answer:
marshall27 [118]3 years ago
8 0

Answer: 24.806

Step-by-step explanation:

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PLS HELP SP=3x+1, and LN=10x−6. Find SP.<br><br> A. 9<br> B. 4<br> C. 21<br> D. 7
Umnica [9.8K]

Step-by-step explanation:

2(sp)=ln

6x+2=10x-6

8=4x

x=2

therefore sp=3×2+1=6+1=7

Option D

5 0
2 years ago
LAST ONE THANKSSSS
pishuonlain [190]

Answer: A

Step-by-step explanation: with my calculation, and the information you have give i have to say it is A.

6 0
2 years ago
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What is the vertex of the graph of f(x) = x2 + 4x + 6?
ICE Princess25 [194]

Answer:

(-2,2)

Step-by-step explanation:

6 0
3 years ago
Which expression is equivalent??? help!
dexar [7]

Answer:

The equivalent expression for the given expression \sqrt[3]{256x^{10}y^{7} } is

4x^{3} y^{2}(\sqrt[3]{4xy} )

Step-by-step explanation:

Given:

\sqrt[3]{256x^{10}y^{7} }

Solution:

We will see first what is Cube rooting.

\sqrt[3]{x^{3}} = x

Law of Indices

(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}

Now, applying above property we get

\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y   )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})

∴ The equivalent expression for the given expression \sqrt[3]{256x^{10}y^{7} } is

4x^{3} y^{2}(\sqrt[3]{4xy} )

5 0
3 years ago
Helppppp i dont know pslßss​
Natali5045456 [20]

Answer:

width=3

Step-by-step explanation:

area=length X width

length=4 X width

=>area=4 X width X width

=>area=(2 X width)^2

=>36=(2 X width)^2

=>6=2 X width

=>width=3

5 0
3 years ago
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