Question

An 80-foot rope from the top of a tree house to the ground forms a 45° angle of elevation from the ground. How high is the top of the tree
house? Round your answer to the nearest tenth of a foot.
feet

Answer 1

Answer:

56.6m

Step-by-step explanation:

Using SOH = opp/hyp

Where θ = 45°

Hpy = 80m

Opp = ?

Sin θ = opp/hpy

Sin 45 = opp/ 80

Sin 45 × 80 = opp

0.7071 × 80 = opp

Opp = 56.568

~ 56.6m

Hence the height of the top of the tree is 56.6m