Answer:
Step-by-step explanation:
Half of the students in Mrs. Hill's class are between 147 centimeters and 154 centimeters tall. (correct)
The median height of the students in Mrs. Hill's class is 152 centimeters. (correct)
The interquartile range of this data set is 15 centimeters. (incorrect, 154-147=17 cm)
The mean height of the students in Mrs. Hill's class is 152.5 centimeters. (we don't get to know the mean height from the graph).
I am pertty sure its 0.6 but if i am wrong sorry
108
I'm not positive but i belive this is correct
3y = 5x + 30
y + 5x = 50 .......(1)
3y - 5x = 30 .....(2) - rearranging the first equation.
Add (1) and (2):-
4y = 80
y = 20
Now plug y = 20 into equation (1):-
20 + 5x = 50
5x = 30
x = 6
The 2 numbers are 6 and 20.
You could try and multiply I believe so .