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2 years ago

If triangle ABC is similar to triangle EHG, find the measure of angle EHG.

Mathematics

2 answers:

Ksju [112]2 years ago

3 0

First we need to find all the interior angles. So we know that the inside of a triangle (all the angles added up) equals 180. So we need to equal all the inside angles to 180. 

2x + x + 60 = 180

Now lets start to solve. First let's subtract the 60 from both sides.

2x + x = 120

Now we need to add the x's together.

3x = 120

Now we must divide the 120 by 3 to get x by itself.

x = 40

Now just replace the x with 40 to find each of the sides. I'm guessing the triangles are reflecting each other so <EHG would be equal to 80.

ALSO to check if 40 would be correct, add all the angles together in the same triangle and they SHOULD add up to be 180! Which they do!

Amiraneli [1.4K]2 years ago

3 0

Step-by-step explanation:

Firstly let's calculate the unknown angles in triangle ABC

2x + x + 60° = 180° { being sum of angles of triangle }

3x = 180° - 60°

3x = 120°

x = 120° / 3

x = 40°

2x = 2 * 40° = 80°

Now since it is said that triangle ABC and triangle EHG are similar so

< EHG = < ABC = 2x = 80°

Hope it will help :)

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x(2-x)=4
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0=x^2-2x+4
use quadratic formula which is
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1x^2-2x+4=0
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x= $\frac{ 2+/-\sqrt{-12} }{2}$
we have $\sqrt{-12}$ and that doesn't give a real solution
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3 years ago

IQ scores are normally distributed with a mean of 100 and a standard deviation of 15.

jekas [21]

Using the normal distribution, it is found that 1851 people would have an IQ less than 115.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 100, \sigma = 15$

The proportion of IQ scores less than 115 is the p-value of Z when X = 115, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{115 - 100}{15}$

Z = 1

Z = 1 has a p-value of 0.8413.

Out of 2200 people:

0.8413 x 2200 = 1851.

More can be learned about the normal distribution at brainly.com/question/27643290

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