I like point point form because it doesn't fail in the no slope case. The line through (a,b) and (c,d) is
(c-a)(y-b) = (d-b)(x-a)
Point slope form is almost the same,
1. (a,b)=(4,0),(c,d)=(-2,1)
y - 0 = (1 - 0)/(-2 - 4) (x - 4)
Answer: y = (-1/6)(x-4)
2.
y - -2 = (3 - -2)/(5 - -3) (x - -3)
Answer: y + 2 = (5/8) (x+3)
3.
y - 1 = (4 - 1)/(3 - -5) (x - -5)
Answer: y - 1 = (3/8) (x+5)
Answer:
The graphs are posted.
Step-by-step explanation:
the method to solve such inequalities is assume the line and then draw the line then search for the inequality
The y < 0.5x-3
First plot the line y=0.5x-3
Now all the values of y which are below the line satisfies the inequality.
similarly for the second question x+y ≥ 5.
Now assume the line x+y=5
All the values of (x , y) above the line satisfies the equation including the points on the line .
