1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lilavasa [31]
3 years ago
10

Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is the trian

gular region with vertices (0, 0), (2, 1), (0, 3); rho(x, y) = 2(x + y)

Mathematics
1 answer:
Alla [95]3 years ago
3 0

Answer: mass (m) = 4 kg

              center of mass coordinate: (15.75,4.5)

Step-by-step explanation: As a surface, a lamina has 2 dimensions (x,y) and a density function.

The region D is shown in the attachment.

From the image of the triangle, lamina is limited at x-axis: 0≤x≤2

At y-axis, it is limited by the lines formed between (0,0) and (2,1) and (2,1) and (0.3):

<u>Points (0,0) and (2,1):</u>

y = \frac{1-0}{2-0}(x-0)

y = \frac{x}{2}

<u>Points (2,1) and (0,3):</u>

y = \frac{3-1}{0-2}(x-0) + 3

y = -x + 3

Now, find total mass, which is given by the formula:

m = \int\limits^a_b {\int\limits^a_b {\rho(x,y)} \, dA }

Calculating for the limits above:

m = \int\limits^2_0 {\int\limits^a_\frac{x}{2}  {2(x+y)} \, dy \, dx  }

where a = -x+3

m = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2}  {(xy+\frac{y^{2}}{2} )} \, dx  }

m = 2.\int\limits^2_0 {(-x^{2}-\frac{x^{2}}{2}+3x )} \, dx  }

m = 2.\int\limits^2_0 {(\frac{-3x^{2}}{2}+3x)} \, dx  }

m = 2.(\frac{-3.2^{2}}{2}+3.2-0)

m = 2(-4+6)

m = 4

<u>Mass of the lamina that occupies region D is 4.</u>

<u />

Center of mass is the point of gravity of an object if it is in an uniform gravitational field. For the lamina, or any other 2 dimensional object, center of mass is calculated by:

M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }

M_{y} = \int\limits^a_b {\int\limits^a_b {x.\rho(x,y)} \, dA }

M_{x} and M_{y} are moments of the lamina about x-axis and y-axis, respectively.

Calculating moments:

For moment about x-axis:

M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }

M_{x} = \int\limits^2_0 {\int\limits^a_\frac{x}{2}  {2.y.(x+y)} \, dy\, dx }

M_{x} = 2\int\limits^2_0 {\int\limits^a_\frac{x}{2}  {y.x+y^{2}} \, dy\, dx }

M_{x} = 2\int\limits^2_0 { ({\frac{y^{2}x}{2}+\frac{y^{3}}{3})}\, dx }

M_{x} = 2\int\limits^2_0 { ({\frac{x(-x+3)^{2}}{2}+\frac{(-x+3)^{3}}{3} -\frac{x^{3}}{8}-\frac{x^{3}}{24}  )}\, dx }

M_{x} = 2.(\frac{-9.x^{2}}{4}+9x)

M_{x} = 2.(\frac{-9.2^{2}}{4}+9.2)

M_{x} = 18

Now to find the x-coordinate:

x = \frac{M_{y}}{m}

x = \frac{63}{4}

x = 15.75

For moment about the y-axis:

M_{y} = \int\limits^2_0 {\int\limits^a_\frac{x}{2}  {2x.(x+y))} \, dy\,dx }

M_{y} = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2}  {x^{2}+yx} \, dy\,dx }

M_{y} = 2.\int\limits^2_0 {y.x^{2}+x.{\frac{y^{2}}{2} } } \,dx }

M_{y} = 2.\int\limits^2_0 {x^{2}.(-x+3)+\frac{x.(-x+3)^{2}}{2} - {\frac{x^{3}}{2}-\frac{x^{3}}{8}  } } \,dx }

M_{y} = 2.\int\limits^2_0 {\frac{-9x^3}{8}+\frac{9x}{2}   } \,dx }

M_{y} = 2.({\frac{-9x^4}{32}+9x^{2})

M_{y} = 2.({\frac{-9.2^4}{32}+9.2^{2}-0)

M{y} = 63

To find y-coordinate:

y = \frac{M_{x}}{m}

y = \frac{18}{4}

y = 4.5

<u>Center mass coordinates for the lamina are (15.75,4.5)</u>

You might be interested in
Is a ratio always a rate?
kari74 [83]
No it is not always a rate that was easy
5 0
2 years ago
Read 2 more answers
What method do i use to solve this?
skelet666 [1.2K]
Answer: x=20
all angles in the triangle are 180 degree, so:
2x+3x+4x=180
9x=180
divide both sides by 9
x= 20
8 0
3 years ago
Anyone who could do these 8 listed questions I will give a generous amount of points. Please make sure to list all the angles th
k0ka [10]

Answer:

1) 0, 180

2) 90

3) 3pi/2

4) pi/2, -3pi/2

5) 90, 270

6) 0

7) pi

8) -2pi, 0, 2pi

Step-by-step explanation:

1) sinx = 0

x = 0, 180, 360

2) sinx = 1

x = 90

3) sinx = -1

x = 270 or 3pi/2

4) sinx = 1

x = pi/2, pi/2 - 2pi = -3pi/2

5) cosx = 0

x = 90, 360

6) cosx = 1

x = 0, 360

7) cosx = -1

x = pi

8) cosx = 1

-2pi, 0 , 2pi

5 0
3 years ago
PLEASE HELP?
Darya [45]

Answer:

1/3

Step-by-step explanation:

The number of people over 40 is 20 + 30 + 35 = 85.

So the probability is 85/255, which reduces to 1/3.

8 0
3 years ago
The students in a science class spent 65% of the class period performing an experiment. how long is a class period if the time s
Kaylis [27]
We let x be the length (in minutes) of a certain science class. 65% of this period is spent with the experiment which lasted for about 52 minutes. Mathematically, this can be expressed as,
                                    52 = (0.65)(x)
The value of x from the generated equation is 80. Thus, the science class is 80 minutes long. 
7 0
3 years ago
Other questions:
  • HELP !! I NEED SOMEONE TO DO THIS TO ME!!
    12·1 answer
  • Whats the unit rate of 5/6 mile in 1/3 hour
    13·1 answer
  • Trapezoid with congruent legs and congruent bases are?
    15·2 answers
  • Type the correct answer in the box.
    12·1 answer
  • Helpp pleasee! 2/9!!!!!
    5·1 answer
  • 1. Stella is planning a birthday party for her little sister. The
    8·2 answers
  • What would you do with "X" and "y"<br> using the substitution method?
    7·1 answer
  • I need this I just finished the testing at this wrong I would like to know what the answer is
    9·2 answers
  • Can yall help wit the numbers and the questions
    6·2 answers
  • Estimate the product by rounding<br><br><br> 9x54
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!