Yes 1c = c.
Technically, the "1" in front of the "c" is called an "implied 1" and, so it's simply written as c.
Here's, an example that should make this clear:
Say c = 4
Then (1)(c) = (1)(4) = 4 = c
1c + 1/4 c
What is a whole plus 1/4? 1 1/4 or 5/4
Same thing here:
c + 1/4 c or 1c + 1/4 c = 1 1/4c or 5/4c
Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6
Answer: An inequality
Step-by-step explanation:
An inequality is a mathematical sentence written with a greater than
sign, or less than sign, or equal to sign or not equal to sign or more than two of these signs at the same time to join two expressions.
Total number of squares = 60 + 80 + 110 + 115 + 95 + 40 = 500
1000/500 = 2 so each little square represents 2 people
60 x 2 as there’s 60 squares from 6-10 so answer is 120